泛函分析2——Normed Linear Spaces
文章目录
- Preface
- FUNCTIONAL ANALYSIS NOTES
- 2 Normed Linear Spaces
- 2.1 Definition
- Examples
- Notation
- Equivalent Norms
- Definiton
- example
- 2.2 Open and Closed Sets
- Definition
- Theorem
- 2.3 Quotient Norm and Quotient Map
- 2.4 Completeness of Normed Linear Spaces
- Definition
- converge of normed linear space sequence
- Cauchy sequence of normed linear space
- Lemma
- Proposition
- Completeness
- 2.5 Series in Normed Linear Spaces
- Definition
- Theorem
- 2.6 Bounded, Totally Bounded, and Compact Subsets of a Normed Linear Space
- Definition
- Proposition
- Theorem
- Remark
- Corollary
Preface
参考摘录于FUNCTIONAL ANALYSIS NOTES——Mr. Andrew Pinchuck
FUNCTIONAL ANALYSIS NOTES
2 Normed Linear Spaces
2.1 Definition
A norm on a linear space XXX is a real-valued function ∥⋅∥:X→R\|\cdot\|: X \rightarrow \mathbb{R}∥⋅∥:X→R which satisfies the following properties:
For all x,y∈Xx, y \in Xx,y∈X and λ∈F\lambda \in \mathbb{F}λ∈F
N1. ∥x∥≥0\|x\| \geq 0∥x∥≥0;
N2. ∥x∥=0⟺x=0\|x\|=0 \Longleftrightarrow x=0∥x∥=0⟺x=0
N3. ∥λx∥=∣λ∣∥x∥\|\lambda x\|=|\lambda|\|x\|∥λx∥=∣λ∣∥x∥
N4. ∥x+y∥≤∥x∥+∥y∥\|x+y\| \leq\|x\|+\|y\|∥x+y∥≤∥x∥+∥y∥ (Triangle Inequality).
A normed linear space is a pair (X,∥⋅∥),(X,\|\cdot\|),(X,∥⋅∥), where XXX is a linear space and ∥⋅∥\|\cdot\|∥⋅∥ a norm on X.X .X. The number ∥x∥\|x\|∥x∥ is called the norm or length of xxx
Unless there is some danger of confusion, we shall identify the normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) with the underlying linear space XXX.
Examples
[1] Let X=FX=\mathbb{F}X=F. For each x∈Xx \in Xx∈X, define ∥x∥=∣x∣\|x\|=|x|∥x∥=∣x∣, then (X,∥⋅∥X,\|\cdot\|X,∥⋅∥)is a normed linear spaces
[2] Let nnn be a natural number and X=FnX=\mathbb{F}^{n}X=Fn. For each x=(x1,x2,…,xn)∈X,x=\left(x_{1}, x_{2}, \ldots, x_{n}\right) \in X,x=(x1,x2,…,xn)∈X, define
∥x∥p=(∑i=1n∣xi∣p)1p,for 1≤p<∞,and ∥x∥∞=max1≤i≤n∣xi∣\begin{array}{l} \|x\|_{p}=\left(\sum_{i=1}^{n}\left|x_{i}\right|^{p}\right)^{\frac{1}{p}}, \text { for } 1 \leq p<\infty, \text { and } \\ \|x\|_{\infty}=\max _{1 \leq i \leq n}\left|x_{i}\right| \end{array} ∥x∥p=(∑i=1n∣xi∣p)p1,for1≤p<∞,and∥x∥∞=max1≤i≤n∣xi∣
Then (X,∥⋅∥p)\left(X,\|\cdot\|_{p}\right)(X,∥⋅∥p) and (X,∥⋅∥∞)\left(X,\|\cdot\|_{\infty}\right)(X,∥⋅∥∞) are normed linear spaces.
[3] Let X=B[a,b]X=\mathcal{B}[a, b]X=B[a,b] be the set of all bounded real-valued functions on [a,b][a, b][a,b]. For each x∈Xx \in Xx∈X, define
∥x∥∞=supa≤t≤b∣x(t)∣\|x\|_{\infty}=\sup _{a \leq t \leq b}|x(t)| ∥x∥∞=a≤t≤bsup∣x(t)∣
Then (X,∥⋅∥∞)\left(X,\|\cdot\|_{\infty}\right)(X,∥⋅∥∞) is a normed linear space.
[4] Let X=C[a,b]={x:[a,b]→F∣xX=\mathcal{C}[a, b]=\{x:[a, b] \rightarrow \mathbb{F} \mid xX=C[a,b]={x:[a,b]→F∣x is continuous }. For each x∈Xx \in Xx∈X, define
$$
\begin{aligned}
|x|_{\infty} &=\sup _{a \leq t \leq b}|x(t)| \
|x|{2} &=\left(\int{a}{b}|x(t)|{2} d t\right)^{\frac{1}{2}}
\end{aligned}
$$
Then (X,∥⋅∥∞)\left(X,\|\cdot\|_{\infty}\right)(X,∥⋅∥∞) and (X,∥⋅∥2)\left(X,\|\cdot\|_{2}\right)(X,∥⋅∥2) are normed linear spaces.
[5] Let X=ℓp,1≤p<∞X=\ell_{p}, 1 \leq p<\inftyX=ℓp,1≤p<∞. For each x=(xi)1∞∈X,x=\left(x_{i}\right)_{1}^{\infty} \in X,x=(xi)1∞∈X, define
∥x∥p=(∑i∈N∣xi∣p)1p\|x\|_{p}=\left(\sum_{i \in \mathbb{N}}\left|x_{i}\right|^{p}\right)^{\frac{1}{p}} ∥x∥p=(i∈N∑∣xi∣p)p1
Then (X,∥⋅∥p)\left(X,\|\cdot\|_{p}\right)(X,∥⋅∥p) is a normed linear space.
[6] Let X=ℓ∞,cX=\ell_{\infty}, cX=ℓ∞,c or c0.c_{0} .c0. For each x=(xi)1∞∈X,x=\left(x_{i}\right)_{1}^{\infty} \in X,x=(xi)1∞∈X, define
∥x∥=∥x∥∞=supi∈N∣xi∣\|x\|=\|x\|_{\infty}=\sup _{i \in \mathbb{N}}\left|x_{i}\right| ∥x∥=∥x∥∞=i∈Nsup∣xi∣
Then XXX is a normed linear space.
[7] Let X=L(Cn)X=\mathcal{L}\left(\mathbb{C}^{n}\right)X=L(Cn) be the linear space of all n×nn \times nn×n complex matrices. For A∈L(Cn),A \in \mathcal{L}\left(\mathbb{C}^{n}\right),A∈L(Cn), let τ(A)=∑i=1n(A)ii\tau(A)=\sum_{i=1}^{n}(A)_{i i}τ(A)=∑i=1n(A)ii be the trace of A.A .A. For A∈L(Cn),A \in \mathcal{L}\left(\mathbb{C}^{n}\right),A∈L(Cn), define
∥A∥2=τ(A∗A)=∑i=1n∑k=1n(A)ki‾(A)ki=∑i=1n∑k=1n∣(A)ki∣2\|A\|_{2}=\sqrt{\tau\left(A^{*} A\right)}=\sqrt{\sum_{i=1}^{n} \sum_{k=1}^{n} \overline{(A)_{k i}}(A)_{k i}}=\sqrt{\sum_{i=1}^{n} \sum_{k=1}^{n}\left|(A)_{k i}\right|^{2}} ∥A∥2=τ(A∗A)
where A∗A^{*}A∗ is the conjugate transpose of the matrix AAA.
Notation
Let aaa be an element of a normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) and r>0.r>0 .r>0.
B(a,r)={x∈X∣∥x−a∥<r}B(a, r)=\{x \in X \mid\|x-a\|<r\}B(a,r)={x∈X∣∥x−a∥<r} (Open ball with centre aaa and radius r)r)r)
B[a,r]={x∈X∣∥x−a∥≤r}B[a, r]=\{x \in X \mid\|x-a\| \leq r\}B[a,r]={x∈X∣∥x−a∥≤r} (Closed ball with centre aaa and radius r)r)r)
S(a,r)={x∈X∣∥x−a∥=r}S(a, r)=\{x \in X \mid\|x-a\|=r\}S(a,r)={x∈X∣∥x−a∥=r} (Sphere with centre aaa and radius r)r)r)
Equivalent Norms
Definiton
Let ∥⋅∥\|\cdot\|∥⋅∥ and ∥⋅∥0\|\cdot\|_{0}∥⋅∥0 be two different norms defined on the same linear space X.X .X. We say that ∥⋅∥\|\cdot\|∥⋅∥ is equivalent to ∥⋅∥0\|\cdot\|_{0}∥⋅∥0 if there are positive numbers α\alphaα and β\betaβ such that
α∥x∥≤∥x∥0≤β∥x∥,for all x∈X\alpha\|x\| \leq\|x\|_{0} \leq \beta\|x\|, \text { for all } x \in X α∥x∥≤∥x∥0≤β∥x∥,for allx∈X
example
all norms on a finite-dimensional normed linear space are equivalent.
2.2 Open and Closed Sets
Definition
[1] A subset SSS of a normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) is open if for each s∈Ss \in Ss∈S there is an ϵ>0\epsilon>0ϵ>0 such that B(s,ϵ)⊂SB(s, \epsilon) \subset SB(s,ϵ)⊂S
[2] A subset FFF of a normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) is closed if its complement X\FX \backslash FX\F is open.
[3] Let SSS be a subset of a normed linear space (X,∥⋅∥).(X,\|\cdot\|) .(X,∥⋅∥). We define the closure of S,S,S, denoted by Sˉ,\bar{S},Sˉ, to be the intersection of all closed sets containing SSS
It is easy to show that SSS is closed if and only if S=SˉS=\bar{S}S=Sˉ.
[4] metric on a set XXX is a real-valued function d:X×X→Rd: X \times X \rightarrow \mathbb{R}d:X×X→R which satisfies the following properties: For all x,y,z∈Xx, y, z \in Xx,y,z∈X,
M1. d(x,y)≥0d(x, y) \geq 0d(x,y)≥0
M2. d(x,y)=0⟺x=yd(x, y)=0 \Longleftrightarrow x=yd(x,y)=0⟺x=y
M3. d(x,y)=d(y,x)d(x, y)=d(y, x)d(x,y)=d(y,x)
M4. d(x,z)≤d(x,y)+d(y,z)d(x, z) \leq d(x, y)+d(y, z)d(x,z)≤d(x,y)+d(y,z)
Theorem
(a) If (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) is a normed linear space, then
d(x,y)=∥x−y∥d(x, y)=\|x-y\| d(x,y)=∥x−y∥
defines a metric on X.X .X. Such a metric ddd is said to be induced or generated by the norm ∥⋅∥.\|\cdot\| .∥⋅∥. Thus, every normed linear space is a metric space, and unless otherwise specified, we shall henceforth regard any normed linear space as a metric space with respect to the metric induced by its norm.
(b) the property of metric d If ddd is a metric on a linear space XXX satisfying the properties: For all x,y,z∈Xx, y, z \in Xx,y,z∈X and for all λ∈F\lambda \in \mathbb{F}λ∈F,
(i) d(x,y)=d(x+z,y+z)(Translation Invariance) d(x, y)=d(x+z, y+z) \quad \text { (Translation Invariance) }d(x,y)=d(x+z,y+z)(Translation Invariance)
(ii) d(λx,λy)=∣λ∣d(x,y)d(\lambda x, \lambda y)=|\lambda| d(x, y) \quadd(λx,λy)=∣λ∣d(x,y) (Absolute Homogeneity),
then
∥x∥=d(x,0)\|x\|=d(x, 0) ∥x∥=d(x,0)
defines a norm on XXX.
2.3 Quotient Norm and Quotient Map
[1] Let MMM be a closed linear subspace of a normed linear space XXX over F\mathbb{F}F. The quotient space X/MX / MX/M is a normed linear space with respect to the norm(Quotient Norm)
∥[x]∥:=infy∈[x]∥y∥=infm∈M∥x+m∥=infm∈M∥x−m∥=d(x,M),where [x]∈X/M\|[x]\|:=\inf _{y \in[x]}\|y\|=\inf _{m \in M}\|x+m\|=\inf _{m \in M}\|x-m\|=d(x, M), \text { where }[x] \in X / M ∥[x]∥:=y∈[x]inf∥y∥=m∈Minf∥x+m∥=m∈Minf∥x−m∥=d(x,M),where[x]∈X/M
infm∈M∥x−m∥=d(x,M)\inf _{m \in M}\|x-m\|=d(x, M)infm∈M∥x−m∥=d(x,M),这个我的理解是,x到m的范数最小,也就是x到M的距离,类比点到直线的距离。
[2] Let MMM be a closed subspace of the normed linear space XXX. The mapping QMQ_{M}QM from X→X/MX \rightarrow X / MX→X/M defined by
QM(x)=x+M,x∈XQ_{M}(x)=x+M, \quad x \in X QM(x)=x+M,x∈X
is called the quotient map (or natural embedding) of XXX onto X/MX / MX/M.
2.4 Completeness of Normed Linear Spaces
Definition
Let (xn)n=1∞\left(x_{n}\right)_{n=1}^{\infty}(xn)n=1∞ be a sequence in a normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥).
converge of normed linear space sequence
(a) (xn)n=1∞\left(x_{n}\right)_{n=1}^{\infty}(xn)n=1∞ is said to converge to xxx if given ϵ>0\epsilon>0ϵ>0 there exists a natural number N=N(ϵ)N=N(\epsilon)N=N(ϵ) such that
∥xn−x∥<ϵfor all n≥N\left\|x_{n}-x\right\|<\epsilon \text { for all } n \geq N ∥xn−x∥<ϵfor alln≥N
Equivalently, (xn)n=1∞\left(x_{n}\right)_{n=1}^{\infty}(xn)n=1∞ converges to xxx if
limn→∞∥xn−x∥=0\lim _{n \rightarrow \infty}\left\|x_{n}-x\right\|=0 n→∞lim∥xn−x∥=0
If this is the case, we shall write
xn→xor limn→∞xn=xx_{n} \rightarrow x \text { or } \lim _{n \rightarrow \infty} x_{n}=x xn→xorn→∞limxn=x
Convergence in the norm is called norm convergence or strong convergence.
Cauchy sequence of normed linear space
(b) (xn)n=1∞\left(x_{n}\right)_{n=1}^{\infty}(xn)n=1∞ is called a Cauchy sequence if given ϵ>0\epsilon>0ϵ>0 there exists a natural number N=N(ϵ)N=N(\epsilon)N=N(ϵ) such that
∥xn−xm∥<ϵfor all n,m≥N\left\|x_{n}-x_{m}\right\|<\epsilon \text { for all } n, m \geq N ∥xn−xm∥<ϵfor alln,m≥N
Equivalently, (xn)\left(x_{n}\right)(xn) is Cauchy if
limn,m→∞∥xn−xm∥=0\lim _{n, m \rightarrow \infty}\left\|x_{n}-x_{m}\right\|=0 n,m→∞lim∥xn−xm∥=0
Cauchy sequence,在序列号趋于无穷大的时候,它的值就趋于稳定了。
Lemma
Let CCC be a closed set in a normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) over F,\mathbb{F},F, and let (xn)\left(x_{n}\right)(xn) be a sequence contained in CCC such that limn→∞xn=x∈X.\lim _{n \rightarrow \infty} x_{n}=x \in X .limn→∞xn=x∈X. Then x∈Cx \in Cx∈C
赋范空间中的闭合子集中的一个序列,如果收敛,则极限值一定在这个闭合子集中。
Let XXX be a normed linear space and AAA a nonempty subset of X.X .X.
[1]∣d(x,A)−d(y,A)∣≤∥x−y∥[1]|d(x, A)-d(y, A)| \leq\|x-y\|[1]∣d(x,A)−d(y,A)∣≤∥x−y∥ for all x,y∈Xx, y \in Xx,y∈X
[2]∣∥x∥−∥y∥∣≤∥x−y∥[2]|\|x\|-\|y\|| \leq\|x-y\|[2]∣∥x∥−∥y∥∣≤∥x−y∥ for all x,y∈Xx, y \in Xx,y∈X
[3] If xn→x,x_{n} \rightarrow x,xn→x, then ∥xn∥→∥x∥\left\|x_{n}\right\| \rightarrow\|x\|∥xn∥→∥x∥
[4] If xn→xx_{n} \rightarrow xxn→x and yn→y,y_{n} \rightarrow y,yn→y, then xn+yn→x+yx_{n}+y_{n} \rightarrow x+yxn+yn→x+y
[5] If xn→xx_{n} \rightarrow xxn→x and αn→α,\alpha_{n} \rightarrow \alpha,αn→α, then αnxn→αx\alpha_{n} x_{n} \rightarrow \alpha xαnxn→αx
[6] The closure of a linear subspace in XXX is again a linear subspace;
[7] Every Cauchy sequence is bounded;
[8] Every convergent sequence is a Cauchy sequence.
Proposition
Let (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) be a normed linear space over F\mathbb{F}F. A Cauchy sequence in XXX which has a convergent subsequence is convergent.
就是说Cauchy sequence 如果有一个收敛的子序列,那么Cauchy sequence也是收敛的
Completeness
[1] A metric space (X,d)(X, d)(X,d) is said to be complete if every Cauchy sequence in XXX converges in XXX.
[2] A normed linear space that is complete with respect to the metric induced by the norm is called a Banach space.
就是说:Banach space是一个metric由norm给出的赋范空间
[3] Theorem Let (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) be a Banach space and let MMM be a linear subspace of X.X .X. Then MMM is complete if and only if the MMM is closed in XXX.
[4] The classical sequence space ℓp\ell_{p}ℓp is complete.
2.5 Series in Normed Linear Spaces
赋范空间中的级数
Definition
[1] Let (xn)\left(x_{n}\right)(xn) be a sequence in a normed linear space (X,∥⋅∥).(X,\|\cdot\|) .(X,∥⋅∥). To this sequence we associate another sequence (sn)\left(s_{n}\right)(sn) of partial sums, where sn=∑k=1nxks_{n}=\sum_{k=1}^{n} x_{k}sn=∑k=1nxk
[2] Definition Let (xn)\left(x_{n}\right)(xn) be a sequence in a normed linear space (X,∥⋅∥).(X,\|\cdot\|) .(X,∥⋅∥). If the sequence (sn)\left(s_{n}\right)(sn) of partial sums converges to s,s,s, then we say that the series ∑k=1∞xk\sum_{k=1}^{\infty} x_{k}∑k=1∞xk converges and that its sum is s.s .s. In this case we write ∑k=1∞xk=s\sum_{k=1}^{\infty} x_{k}=s∑k=1∞xk=s. The series ∑k=1∞xk\sum_{k=1}^{\infty} x_{k}∑k=1∞xk is said to be absolutely convergent if ∑k=1∞∥xk∥<∞.\sum_{k=1}^{\infty}\left\|x_{k}\right\|<\infty .∑k=1∞∥xk∥<∞.
用部分和的形式定义赋范空间中的级数收敛
Theorem
[1] A normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) is a Banach space if and only if every absolutely convergent series in XXX is convergent.
[2] Let MMM be a closed linear subspace of a Banach space X.X .X. Then the quotient space X/MX / MX/M is a Banach space when equipped with the quotient norm.
2.6 Bounded, Totally Bounded, and Compact Subsets of a Normed Linear Space
Definition
[1] A subset AAA of a normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) is bounded if A⊂B[x,r]A \subset B[x, r]A⊂B[x,r] for some x∈Xx \in Xx∈X and r>0r>0r>0
It is clear that AAA is bounded if and only if there is a C>0C>0C>0 such that ∥a∥≤C\|a\| \leq C∥a∥≤C for all a∈Aa \in Aa∈A.
[2] Let AAA be a subset of a normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) and ϵ>0.\epsilon>0 .ϵ>0. A subset Aϵ⊂XA_{\epsilon} \subset XAϵ⊂X is called an ϵ\epsilonϵ -net for AAA if for each x∈Ax \in Ax∈A there is an element y∈Aϵy \in A_{\epsilon}y∈Aϵ such that ∥x−y∥<ϵ.\|x-y\|<\epsilon .∥x−y∥<ϵ. Simply put, Aϵ⊂XA_{\epsilon} \subset XAϵ⊂X is an ϵ\epsilonϵ -net for AAA if each element of AAA is within an ϵ\epsilonϵ distance to some element of AϵA_{\epsilon}Aϵ
AϵA_\epsilonAϵ表示这样一个集合,对于A中的每一个元素a你总能在AϵA_\epsilonAϵ中找到对应的某个元素aϵa_\epsilonaϵ,使得它俩的distance在ϵ\epsilonϵ内。
A subset AAA of a normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) is totally bounded (or precompact) if for any ϵ>0\epsilon>0ϵ>0 there is a finite ϵ\epsilonϵ -net Fϵ⊂XF_{\epsilon} \subset XFϵ⊂X for AAA. That is, there is a finite set Fϵ⊂XF_{\epsilon} \subset XFϵ⊂X such that
A⊂⋃x∈FϵB(x,ϵ)A \subset \bigcup_{x \in F_{\epsilon}} B(x, \epsilon) A⊂x∈Fϵ⋃B(x,ϵ)
Proposition
[1] Every totally bounded subset of a normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) is bounded.
[2] A subset AAA of a normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) is totally bounded if and only if for any ϵ>0\epsilon>0ϵ>0 there is a finite set Fϵ⊂AF_{\epsilon} \subset AFϵ⊂A such that
A⊂⋃x∈FϵB(x,ϵ)A \subset \bigcup_{x \in F_{\epsilon}} B(x, \epsilon) A⊂x∈Fϵ⋃B(x,ϵ)
[3] A normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) is sequentially compact if every sequence in XXX has a convergent subsequence.
Theorem
[1] A subset KKK of a normed linear space (X,∥⋅∥)(X,\|\cdot\|)(X,∥⋅∥) is totally bounded if and only if every sequence in KKK has a Cauchy subsequence.
[2] A subset of a normed linear space is sequentially compact if and only if it is totally bounded and complete .
Remark
It can be shown that on a metric space, compactness and sequential compactness are equivalent. Thus, it follows, that on a normed linear space, we can use these terms interchangeably.
Corollary
[1] A subset of a Banach space is sequentially compact if and only if it is totally bounded and closed
[2] A sequentially compact subset of a normed linear space is closed and bounded.
[3] A closed subset F of a sequentially compact normed linear space (X;∥⋅∥)(X; \|\cdot\|)(X;∥⋅∥)is sequentially compact.
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