1050 String Subtraction (20 分)

立志用最少的代码做最高效的表达

PAT甲级最优题解——>传送门

Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However, it might not be that simple to do it fast.

Input Specification:
Each input file contains one test case. Each case consists of two lines which gives S1 and S2, respectively. The string lengths of both strings are no more than 104. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

Output Specification:
For each test case, print S1−S2 in one line.

Sample Input:
They are students.
aeiou

Sample Output:
Thy r stdnts.

查询表算法。

#include<bits/stdc++.h>
using namespace std;
int a[300];
int main() {string s1, s2; getline(cin, s1);  getline(cin, s2);for(auto i : s2) a[i]++;for(auto i : s1) if(a[i] == 0) cout << i;return 0;
}

耗时：

求赞哦~ (✪ω✪)

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1050 String Subtraction (20 分)_10行代码AC

立志用最少的代码做最高效的表达

耗时：

求赞哦~ (✪ω✪)

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