本文实例为大家分享了C语言编写五子棋游戏的具体代码，供大家参考，具体内容如下

一、构建棋盘

首先可以用一个二维数组来构建棋盘，下标表示位置，内容表示黑子白子或者空位。当数组内容为1时，该位置为白字，当数组为0时，该位置为白子，空位输出+

int w[11][11], flag = 0;

int a, b;

for (int k = 0; k < 11; k++)

printf("第%d列\t", k);

printf("\n");

for (int i = 0; i < 11; i++) {

for (int j = 0; j < 11; j++) {

if (w[i][j] == 0) printf("黑\t");

else if (w[i][j] == 1) printf("白\t");

else printf("+\t");

}

printf("第%d行\n\n", i);

}

二、判断位置超范围与错误输入

当输入的棋子坐标超出范围或者该位置已经存在棋子，则再次输入棋子坐标。其中flag作为标志作为判别黑手白手的标志。

if (flag == 0) {

printf("黑色下棋\n");

scanf("%d %d", &a, &b);

while (a < 0 || a>10 || b < 0 || b>10) {

printf("此位置超出范围，请重新输入：");

scanf("%d %d", &a, &b);

}

while (w[a][b] == 0 || w[a][b] == 1)

{

printf("此位置已有棋子，请重新输入：");

scanf("%d %d", &a, &b);

}

flag = 1;

w[a][b] = 0;

}

else {

printf("白色下棋\n");

scanf("%d %d", &a, &b);

while (a < 0 || a>10 || b < 0 || b>10) {

printf("此位置超出范围，请重新输入：");

scanf("%d %d", &a, &b);

}

while (w[a][b] == 0 || w[a][b] == 1)

{

printf("此位置已有棋子，请重新输入：");

scanf("%d %d", &a, &b);

}

三、判断胜负

在五子棋中，出现五个棋子排成一排或者一列或者斜排即可判为胜出。每当落下一个棋子，对该棋子前后上下斜排五个棋子进行判别，超过五个连续的一样颜色的棋子则胜出。

int A = 1, B = 1, jieguo = 0, C = 1, D = 1;

int x = 1, y = 1, m = 1, n = 1;

if (w[a][b] == 1) {

for (int i = 1; i < 5; i++) {

if (w[a][b + i] == 1) A++;

else break;

}

for (int i = 1; i < 5; i++) {

if (w[a][b - i] == 1) A++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a+i][b] == 1) C++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a - i][b] == 1) C++;

else break;

}

if (A > 4 || C > 4) jieguo = 1;//白棋胜利标志

else {

for (int i = 1; i < 5; i++) {

if (w[a+i][b + i] == 1) x++;

else break;

}

for (int i = 1; i < 5; i++) {

if (w[a-i][b - i] == 1) x++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a + i][b-i] == 1) y++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a - i][b+i] == 1) y++;

else break;

}

if (x > 4 || y > 4) jieguo = 1;

}

}

if (w[a][b] == 0) {

for (int i = 1; i < 5; i++) {

if (w[a][b + i] == 0) B++;

else break;

}

for (int i = 1; i < 5; i++) {

if (w[a][b - i] == 0) B++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a + i][b] == 0) D++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a - i][b] == 0) D++;

else break;

}

if (B > 4 || D > 4) jieguo = 2;//黑棋胜利标志

else {

for (int i = 1; i < 5; i++) {

if (w[a + i][b + i] == 0) m++;

else break;

}

for (int i = 1; i < 5; i++) {

if (w[a - i][b - i] == 0) m++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a + i][b - i] == 0) n++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a - i][b + i] == 0) n++;

else break;

}

if (m > 4 || n > 4) jieguo = 2;

}

}

程序完成

四、演示结果

五、源代码

int main() {

int w[11][11], flag = 0;

int a, b;

while (1) {

if (flag == 0) {

printf("黑色下棋\n");

scanf("%d %d", &a, &b);

while (a < 0 || a>10 || b < 0 || b>10) {

printf("此位置超出范围，请重新输入：");

scanf("%d %d", &a, &b);

}

while (w[a][b] == 0 || w[a][b] == 1)

{

printf("此位置已有棋子，请重新输入：");

scanf("%d %d", &a, &b);

}

flag = 1;

w[a][b] = 0;

}

else {

printf("白色下棋\n");

scanf("%d %d", &a, &b);

while (a < 0 || a>10 || b < 0 || b>10) {

printf("此位置超出范围，请重新输入：");

scanf("%d %d", &a, &b);

}

while (w[a][b] == 0 || w[a][b] == 1)

{

printf("此位置已有棋子，请重新输入：");

scanf("%d %d", &a, &b);

}

flag = 0;

w[a][b] = 1;

}

int A = 1, B = 1, jieguo = 0, C = 1, D = 1;

int x = 1, y = 1, m = 1, n = 1;

if (w[a][b] == 1) {

for (int i = 1; i < 5; i++) {

if (w[a][b + i] == 1) A++;

else break;

}

for (int i = 1; i < 5; i++) {

if (w[a][b - i] == 1) A++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a+i][b] == 1) C++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a - i][b] == 1) C++;

else break;

}

if (A > 4 || C > 4) jieguo = 1;//白棋胜利标志

else {

for (int i = 1; i < 5; i++) {

if (w[a+i][b + i] == 1) x++;

else break;

}

for (int i = 1; i < 5; i++) {

if (w[a-i][b - i] == 1) x++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a + i][b-i] == 1) y++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a - i][b+i] == 1) y++;

else break;

}

if (x > 4 || y > 4) jieguo = 1;

}

}

if (w[a][b] == 0) {

for (int i = 1; i < 5; i++) {

if (w[a][b + i] == 0) B++;

else break;

}

for (int i = 1; i < 5; i++) {

if (w[a][b - i] == 0) B++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a + i][b] == 0) D++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a - i][b] == 0) D++;

else break;

}

if (B > 4 || D > 4) jieguo = 2;//黑棋胜利标志

else {

for (int i = 1; i < 5; i++) {

if (w[a + i][b + i] == 0) m++;

else break;

}

for (int i = 1; i < 5; i++) {

if (w[a - i][b - i] == 0) m++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a + i][b - i] == 0) n++;

else break;

}

for (int i = 1; i < 5; i++)

{

if (w[a - i][b + i] == 0) n++;

else break;

}

if (m > 4 || n > 4) jieguo = 2;

}

}

for (int k = 0; k < 11; k++)

printf("第%d列\t", k);

printf("\n");

for (int i = 0; i < 11; i++) {

for (int j = 0; j < 11; j++) {

if (w[i][j] == 0) printf("黑\t");

else if (w[i][j] == 1) printf("白\t");

else printf("+\t");

}

printf("第%d行\n\n", i);

}

if (jieguo == 1) {

printf("白棋胜利");

break;

}

if (jieguo == 2) {

printf("黑棋胜利");

break;

}

}

return 0;

}

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持脚本之家。