LeetCode Longest Increasing Subsequence(动态规划、二分法)

问题：求数组的最长上升子序列问题

思路：第一种方法使用动态规划方法，用dp(i)来表示从0到i之间的最长上升子序列的长度。状态转移方程为dp(i)=max{dp(j)+1},其中0<=j<i，并且有 nums[i] > nums[j]

第二种方法是用d(i)来表示最长上升子序列长度为i时，d(i)的值是最小的。

具体代码参考：

https://github.com/wuli2496/OJ/tree/master/LeetCode/Longest%20Increasing%20Subsequence

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LeetCode Longest Increasing Subsequence(动态规划、二分法)

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