浸润边界(IB)下二维圆柱绕流,bug1.0版

import numpy as np
from math import sqrt
from numpy import pi as PI
from numpy import sin,cos
import matplotlib.pyplot as plt
from matplotlib import cm
import matplotlib
matplotlib.use('Agg')
# 读取拉格朗日点
def read_IB_Points(struct_name):filename = struct_name+'.ibpoint'with open(filename) as f:Nb = int(f.readline().strip())xLag,yLag = np.loadtxt(f,unpack=True) # unpack将每一列当成一个向量输出return(Nb,xLag,yLag)

######### def ##############

# 找近邻邻居点
def give_1D_NoneDelta_Indices(xy_Lag,N_xy,d_xy):delta = 4ind = np.floor(xy_Lag/d_xy + 1) # np.floor向下取整indices = np.tile(ind,(delta,1)).T # np.tile扩展数组indices += -delta/2+1+np.arange(delta)indices = (indices-1)%N_xyreturn indices
def give_NonZero_Delta_Indices_XY(xLag,yLag,Nx,Ny,dx,dy):delta = 4xInds = give_1D_NoneDelta_Indices(xLag,Nx,dx)yInds = give_1D_NoneDelta_Indices(yLag,Ny,dy)xInds = np.tile(xInds,(1,delta))yInds = np.tile(yInds,(1,delta))return(xInds.astype('int'),yInds.astype('int'))
def give_Eulerian_Lagrangian_distance(x,y,L):distance = np.abs(x-y)distance = np.minimum(distance,L-distance)return distance
def give_Delta_Kernel(x,dx):RMAT = np.abs(x)/dxdelta = RMATrow,col = x.shapefor ii in range(row):for jj in range(col):r = RMAT[ii,jj]if r<1:delta[ii,jj] = ( (3 - 2*r + sqrt(1 + 4*r - 4*r*r) ) / (8*dx) )elif (r<2) and (r>=1):delta[ii,jj] = ( (5 - 2*r - sqrt(-7 + 12*r - 4*r*r) ) / (8*dx) )else:delta[ii,jj] = 0return delta
def give_Me_Perturbed_Distance(U,V,dx,dy,delta_X,delta_Y,xInds,yInds):mat_X = U[xInds,yInds]*delta_X*delta_Ymat_Y = V[xInds,yInds]*delta_X*delta_Ymove_X = mat_X.sum(1) * (dx*dy)move_Y = mat_Y.sum(1) * (dx*dy)return(move_X, move_Y)
# step 1 更新拉格朗日边界位置
def please_Move_Lagrangian_Point_Positions(x,y,Nx,Ny,Lx,Ly,dx,dy,Nb,ds,xLag,yLag,U,V,xL_P,yL_P,dt):delta = 4Nx = NxNy = NyLx = LxLy = Lydx = dxdy = dyNb = Nbds = dsU = UV = Vdt = dtxInds, yInds = give_NonZero_Delta_Indices_XY(xLag,yLag,Nx,Ny,dx,dy)xLH_aux = xLag % LxyLH_aux = yLag % LyxL_H_ReSize = np.tile(xLH_aux,(delta**2,1)).TyL_H_ReSize = np.tile(yLH_aux,(delta**2,1)).T#     if(np.isscalar(xL_P)):distX = give_Eulerian_Lagrangian_distance(x[xInds],xL_H_ReSize,Lx)distY = give_Eulerian_Lagrangian_distance(y[yInds],yL_H_ReSize,Ly)
#     else:
#         distX = give_Eulerian_Lagrangian_distance(x[xInds],xL_H_ReSize,Lx)
#         distY = give_Eulerian_Lagrangian_distance(y[yInds],yL_H_ReSize,Ly)delta_X = give_Delta_Kernel(distX,dx)delta_Y = give_Delta_Kernel(distY,dy)move_X, move_Y = give_Me_Perturbed_Distance(U,V,dx,dy,delta_X,delta_Y,xInds,yInds)xL_Next = xL_P + dt * move_XyL_Next = yL_P + dt * move_Yreturn(xL_Next,yL_Next)

########### def #####

def give_Me_Delta_function_approximations_For_Force_Calc(Nx,Ny,Lx,Ly,dx,dy,Nb,x,y,xLag,yLag):delta = 4Nx = NxNy = NyLx = LxLy = Lydx = dxdy = dyNb = NbindX = give_1D_NoneDelta_Indices(xLag, Nx, dx)indY = give_1D_NoneDelta_Indices(xLag, Ny, dy)indLagAux = np.arange(Nb)ind_Lag = np.tile(indLagAux,(delta,1)).T.astype('int')distX = give_Eulerian_Lagrangian_distance(x[indX.astype('int')],xLag[ind_Lag],Lx)distY = give_Eulerian_Lagrangian_distance(y[indY.astype('int')],yLag[ind_Lag],Ly)# 初始化delta_X和Y矩阵delta_X = np.zeros((Nb,Nx))delta_Y = np.zeros((Ny,Nb))delta_1D_x = give_Delta_Kernel(distX,dx)delta_1D_y = give_Delta_Kernel(distY,dy)delta_X[ind_Lag,indX.astype('int')] = delta_1D_xdelta_Y[indY.astype('int'),ind_Lag] = delta_1D_yreturn(delta_X,delta_Y)
# step 2 计算来自拉格朗日点的力
def please_Find_Lagrangian_Forces_On_Eulerian_grid(Nx,Ny,Lx,Ly,dx,dy,Nb,ds,xLag,yLag,x,y):delta = 4Nx = NxNy = NyLx = LxLy = Lydx = dxdy = dyNb = Nbds = dsfx = np.zeros(Nb)fy = np.zeros(Nb)# 保存拉格朗日力F_Lag = np.empty((fx.size,2))F_Lag[:,0] = fxF_Lag[:,1] = fydelta_X,delta_Y = give_Me_Delta_function_approximations_For_Force_Calc(Nx,Ny,Lx,Ly,dx,dy,Nb,x,y,xLag,yLag)fxds = np.diag(fx*ds)fyds = np.diag(fy*ds)Fx = delta_Y @ fxds @ delta_XFy = delta_Y @ fyds @ delta_Xreturn(Fx.T,Fy.T,F_Lag)

############ def ########

LBM

def give_Me_Macroscopic_Rho_U(fin, Fx, Fy, dt,Nx,Ny,v):rho = np.sum(fin, axis=0)u = np.zeros((2,Nx,Ny))for i in range(9):u[0,:,:] = (v[i,0] * fin[i,:,:])/rho + Fx*dt/(2*rho)u[1,:,:] = (v[i,1] * fin[i,:,:])/rho + Fy*dt/(2*rho)U = u[0,:,:]V = u[1,:,:]return(rho,u,U,V)
# 平衡态计算
def equilibrium(rho, u, Nx, Ny,v,t):usqr = 3/2 * (u[0]**2 + u[1]**2)feq = np.zeros((9, Nx, Ny))for i in range(9):cu = 3 * (v[i,0]*u[0,:,:] + v[i,1]*u[1,:,:])feq[i,:,:] = rho*t[i] * (1 + cu + 0.5*cu**2 - usqr)return feq
# 初始速度曲线:几乎为零,有一个轻微的扰动来触发不稳定。
def inivel(d, x, y):return (1-d) * 0.04 * (1+1e-4*sin(y/2*2*PI))
def please_Exe_LBM(Nx,Ny,fin,vel,Fx,Fy,dt,v,t,omega):col1 = np.array([0, 1, 2])col2 = np.array([3, 4, 5])col3 = np.array([6, 7, 8])fin[col3, -1, :] = fin[col3, -2, :]rho,u,U,V = give_Me_Macroscopic_Rho_U(fin,Fx,Fy,dt,Nx,Ny,v)u[:, 0, :] = vel[:, 0, :]U[0,:] = vel[0,0,:]V[0,:] = vel[1,0,:]rho[0,:] = 1/(1-u[0,0,:]) * (np.sum(fin[col2,0,:], axis=0) + 2*np.sum(fin[col3,0,:], axis=0))feq = equilibrium(rho,u,Nx,Ny,v,t)fin[[0,1,2],0,:] = feq[[0,1,2],0,:]+fin[[8,7,6],0,:]-feq[[8,7,6],0,:]fout = fin - omega * (fin - feq)for i in range(9):fin[i, :, :] = np.roll(np.roll(fout[i,:,:],v[i,0], axis=0), v[i,1], axis=1)return(fin,vel,U,V)
def main():struct_name = 'cylinder'Time = 3.5dt = 0.005current_time = 0i = 1Nx = 40Ny = 20Lx = 40Ly = 20dx = Lx/Nxdy = Ly/Nyds = Lx/(2.*Nx)cx, cy, r = Nx//4, Ny//2, Ny//9  # 圆柱坐标Re = 220.0         # 雷诺数uLB = 0.04        # 模型的入口速度nulb = uLB*r/Re   # 粘性系数omega = 1/(3*nulb+0.5)  # 松弛频率ly = Ny-1         # 用于计算入口,为模型增加扰动,当雷诺数较小时,计算缺少扰动v = np.array([[1,1], [1,0], [1,-1],[0,1], [0,0], [0,-1],[-1,1], [-1,0], [-1,-1]])t = np.array([1/36, 1/9, 1/36,1/9, 4/9, 1/9,1/36, 1/9, 1/36])# 创建欧拉格点x = np.arange(0, Lx, dx)y = np.arange(0, Ly, dy)X,Y = np.meshgrid(x, y)# 读取拉格朗日节点Nb,xLag,yLag = read_IB_Points(struct_name)xLag_P = xLag #初始化前拉格朗日点yLag_P = yLagU = np.zeros((Nx,Ny)) # 初始化速度V = np.zeros((Nx,Ny))vel = np.fromfunction(inivel, (2, Nx, Ny))fin = equilibrium(1,vel,Nx,Ny,v,t)while current_time < Time:# step1:更新拉格朗日点位置xLag_h,yLag_h = please_Move_Lagrangian_Point_Positions(x,y,Nx,Ny,Lx,Ly,dx,dy,Nb,ds,xLag,yLag,U,V,xLag,yLag,dt)
#         print('xLag_h')
#         print(xLag_h)# step2:计算来自拉格朗日点的力Fx,Fy,F_Lag = please_Find_Lagrangian_Forces_On_Eulerian_grid(Nx,Ny,Lx,Ly,dx,dy,Nb,ds,xLag,yLag,x,y)
#         print('Fx')
#         print(Fx)# step3:LBMfin,vel,U,V = please_Exe_LBM(Nx,Ny,fin, vel, Fx, Fy, dt, v, t, omega)
#         print('U')
#         print(U[15])#step4:更新拉格朗日点的位置xLag_P = np.array(xLag_h)yLag_P = np.array(yLag_h)xLag,yLag = please_Move_Lagrangian_Point_Positions(x,y,Nx,Ny,Lx,Ly,dx,dy,Nb,ds,xLag,yLag,U,V,xLag_P,yLag_P,dt)
#         print('xLag_P')
#         print(xLag_P)
#         print('xLag')
#         print(xLag)current_time += dt#         wait = input('Press enter to contiune...')#可视化xlabel = str(current_time)+' s'plt.figure(figsize=(8, 4))
#         plt.clf()plt.xlabel(xlabel)plt.axis('equal')plt.plot(xLag,yLag,'r-',xLag,yLag,'*')plt.imshow(np.sqrt(U**2+V**2).transpose(), cmap=cm.Reds)plt.savefig("/share/home/yszhang/PBS/LBM/IB_D2Q9/pic/"+str(i)+".jpg")i += 1
main()
import cv2file_dir = '/share/home/yszhang/PBS/LBM/IB_D2Q9/pic/'
video = cv2.VideoWriter('video.avi',cv2.VideoWriter_fourcc(*'MJPG'),5,(1280,720))for i in range(1,701):img = cv2.imread(file_dir+str(i)+'.jpg')     img = cv2.resize(img,(1280,720))video.write(img)video.release()

LBM学习记录5 Python实现IB二维圆柱绕流 1.0相关推荐

  1. fluent二维叶型仿真_ICEM划分嵌套网格之二维圆柱绕流

    首先,介绍一下嵌套网格.网络上关于嵌套网格的的内容大多数是关于直接利用软件进行计算的过程,而对于前处理过程中的网格生成过程并没有什么描述,其实这种技术已经在学术界流传已久,只是用的都是自己的程序算法, ...

  2. matlab圆柱饶流,有限元法解二维圆柱绕流问题.pdf

    目    录 目    录 1 1.  问题描述 1 2.  相关的有限元理论基础  1 2.1 二次泛函极值原理和里兹解法  1 2.2 伽辽金加权余数法  2 3.  二维圆柱绕流的有限元解法   ...

  3. LBM学习记录3 Python实现D2Q9圆柱绕流

    在https://blog.csdn.net/weixin_58913471/article/details/117561995?spm=1001.2101.3001.6650.1&utm_m ...

  4. java学习记录十五:集合二Collections、Set、Map

    java学习记录十五:集合二 一.Collections工具类 一.解释 二.常用方法 1.打乱集合顺序 2.按照默认规则排序 3.按指定规则排序 4.批量添加元素 二.可变参数 一.解释 二.写法 ...

  5. Python生成动态二维码,运用神库:qrcode

    一.介绍 1.1 二维码 二维码又称二维条码,常见的二维码为 QR Code,QR 全称 Quick Response.是一个近几年来移动设备上超流行的一种编码方式,在现在的生活中二维码随处可见.我们 ...

  6. python myqr制作二维码生成器_用Python生成动态二维码,只要5行代码,拥有你的个性二维码!...

    原标题:用Python生成动态二维码,只要5行代码,拥有你的个性二维码! 前言 文的文字及图片来源于网络,仅供学习.交流使用,不具有任何商业用途,版权归原作者所有,如有问题请及时联系我们以作处理. P ...

  7. 如何用python制作动态二维码,提升表白成功率?

    来源:凹凸数据 本文约1000字,建议阅读5分钟. 本文教你用python制作动态二维码,助你表白成功! 关注数据派THU(DatapiTHU)后台回复"20200520"获取完整 ...

  8. 深入浅出python机器学习_如何用python画(绘制)二维函数(二维图)?

    参考文档 python 如何绘制二维函数? from matplotlib import pyplot as plt import numpy as np low=lambda x:10000 if ...

  9. Python+OpenCV:二维直方图(2D Histograms)

    Python+OpenCV:二维直方图(2D Histograms) ################################################################# ...

最新文章

  1. jsp自定自定义标签
  2. SQL Tips:兼顾检索速度和精确性
  3. 11.MapReduce第1部分
  4. 2020年快手校招JAVA岗笔试第一题
  5. Firewalld防火墙应用
  6. sql server 2008安装_性能不够?基于时序数据库的Zabbix 5.2安装指南
  7. c语言volatile关键字的作用是什么?
  8. AVS游程解码、反扫描、反量化和反变换优化设计
  9. spring教程笔记4
  10. 【人脸识别】基于matlab GUI PCA+SVM人脸识别(准确率)【含Matlab源码 823期】
  11. 浏览器自动调html5,HTML与浏览器
  12. 物联网轻松上云实践 之 HaaS样板间
  13. 阿里P7级别面试经验总结,面试心得体会
  14. android俄罗斯方块报告,Android 俄罗斯方块
  15. zotero+坚果云+PDF Expert实现ipad与windows文献阅读同步
  16. 服务器网卡光模块位置,收藏:详解服务器、磁盘和网卡知识
  17. 【论文阅读】8-Non-local Scan Consolidation for 3D Urban Scenes
  18. 营业增加值公式简要解析
  19. 从“半部电台”到“云监工” 天翼云助力红色电信启航新征程
  20. PCIE及南桥芯片组

热门文章

  1. 此页面上的脚本造成Web浏览器运行速度减慢。如果继续运行,您的计算机将可能停止响应。...
  2. Android开发,使用Log打印日志,打印相同内容在Logcat中只能连续显示两次(遍历打印List中的内容,打印结果条数比List的size小)。
  3. 讲给后台程序员看的前端系列教程(02)——HTML5标签(1)
  4. mysql提取5号的数据库_五、各类数据库信息的提取
  5. Robotframework+Appium+夜神模拟器环境搭建(1)
  6. python人脸签到_人脸实时签到(three.js+tracking.js)基于浏览器
  7. Python实现自动扫雷,轻松挤上世界排行榜,破世界纪录~
  8. 计算机主机耗电量,主编教您电脑耗电量如何计算
  9. T-SQL:表的创建和管理
  10. Dart编程语言从基础到进阶3