LeetCode171——Excel Sheet Column Number

　　很简单的一道题，输出excel中字母对应的数字。但是由于自己的程序思想还是很差，代码很长。

class Solution
{
public:int titleToNumber(string s){int ans = 0;int tmp = 1;auto len = s.size();if (len == 1){return letterToNumber(s[0]);}for (auto i = 0; i != len; ++ i){ans += letterToNumber(s[i]) * pow(26,(len - tmp));tmp ++;}ans += letterToNumber(s[len - tmp]);return ans;}int letterToNumber(char p){int ans = 0;switch(p){case 'A':ans = 1;break;case 'B':ans = 2;break;case 'C':ans = 3;break;case 'D':ans = 4;break;case 'E':ans = 5;break;case 'F':ans = 6;break;case 'G':ans = 7;break;case 'H':ans = 8;break;case 'I':ans = 9;break;case 'J':ans = 10;break;case 'K':ans = 11;break;case 'L':ans = 12;break;case 'M':ans = 13;break;case 'N':ans = 14;break;case 'O':ans = 15;break;case 'P':ans = 16;break;case 'Q':ans = 17;break;case 'R':ans = 18;break;case 'S':ans = 19;break;case 'T':ans = 20;break;case 'U':ans = 21;break;case 'V':ans = 22;break;case 'W':ans = 23;break;case 'X':ans = 24;break;case 'Y':ans = 25;break;case 'Z':ans = 26;break;default:break;}return ans;}
};

看了别人的代码之后，深深感觉自己的弱小。他们利用了ascii码极大的减少了switch case 的繁琐。

int titleToNumber(string s) {int len = s.length(), sum=0;for(int i=0;i<len;i++)sum += (int(s[i]-'A'+1))*pow(26,len-1-i);return sum;
}

短短几行代码就将这个问题解决了，看来学习之路还很漫长！加油！！！！！！！

转载于:https://www.cnblogs.com/thewaytomakemiracle/p/5039548.html

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