Educational Codeforces Round 39 A Partition

传送门

分治就好了，哈哈大于小于0的数据分开算

#include <bits/stdc++.h>
using namespace std;
typedef long long ll ;
typedef double    dl ;
#define INF 0x7fconst int  inf = 987654321;
const int sz = 1e6 + 5;
const int mod = 1e9 + 7;
const int sqrtn = 300;#define f(i,l,r) for(int i=l;i<=r;++i)
#define g(i,l,r) for(int i=l;i>=r;--i)
#define CLR(arr,val) memset(arr,val,sizeof(arr))
#define sz(a)   strlen(a)
#define FAST_IO ios::sync_with_stdio(false);cin.tie(0);#define lowbit(x) x&(-x)
#define X first
#define Y second #define pb push_back
#define pii pair<int,int>int dir[8][2]={{1,0},{-1,0},{0,1},{0,-1},{1,1},{1,-1},{-1,1},{-1,-1}};
int n;
int a ,mx,mn;
void work()
{cin>>n;f(i,1,n){cin>>a;if(a>0)mx+=a;else mn+=a;}cout<<mx-mn<<endl;
}int main()
{FAST_IO ;freopen("in","r",stdin);freopen("out","w",stdout);work();return 0;
}

转载于:https://www.cnblogs.com/corx/p/8523829.html

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