IRR计算 - 盈利能力的评价【难度:2级】:

答案1:

def irr(c):precision, guess, v, lastPositiveGuess, lastNegativeGuess = 0.000001, 0.5, 0, None, Noneif all([ i ==0 for i in c]):return 0if all([i >= 0 for i in c]) or all([i <= 0 for i in c]):return Nonecalc = lambda g : sum([item/pow(1+g, i) for i, item in enumerate(c)])while True:v = calc(guess)if abs(v) < precision:return guessif v > 0:lastPositiveGuess = guessif lastNegativeGuess is not None:guess = (lastNegativeGuess + guess)/2else:guess = guess * 2else:lastNegativeGuess = guessif lastPositiveGuess is not None:guess = (lastPositiveGuess + guess)/2else:guess = guess / 2

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IRR计算 - 盈利能力的评价【难度:2级】:

答案1:

Python练习题答案: IRR计算 - 盈利能力的评价【难度：2级】--景越Python编程实例训练营,1000道上机题等你来挑战相关推荐

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