Python练习题答案: 摩门经【难度:2级】--景越Python编程实例训练营,1000道上机题等你来挑战
摩门经【难度:2级】:
答案1:
from math import log, ceil
def mormons(starting_number, reach, target):return ceil( log(target/starting_number) / log(1+reach) )
答案2:
def mormons(starting_number, reach, target):missions = 0while starting_number < target:starting_number += starting_number * reachmissions += 1return missions# def mormons(start, reach, target, missions=0):
# if start >= target:
# return missions
# return mormons(start + (start * reach), reach, target, missions + 1)
答案3:
def mormons(start, fac, target):return 0 if start >= target else 1 + mormons(start * (fac + 1), fac, target)
答案4:
import math
def mormons(starting_number, reach, target):return math.ceil(math.log(target/starting_number,reach+1))
答案5:
from math import ceil, logdef mormons(n, r, target):return ceil(log(target/n, r+1))
答案6:
def mormons(n, r, target):c = 0while n < target:n *= r + 1c += 1return c
答案7:
def mormons(starting_number, reach, target):return 0 if starting_number>=target else 1+mormons(starting_number*(1+reach), reach, target)
答案8:
def mormons(number, reach, target):c = 0while number < target:number += reach*numberc += 1return c
答案9:
def mormons(m, reach, target):t = 0while m < target:m, t = m * reach + m, t + 1return t
答案10:
mormons=m=lambda s,r,t:s<t and-~m(-~r*s,r,t)
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