1 /*
  2     set的二分查找
  3     如果数据规模小的话可以用O(n^2)的暴力想法
  4     否则就只好一个一个的换(a, b, c)，在set容器找相匹配的
  5 */
  6 #include <cstdio>
  7 #include <cmath>
  8 #include <string>
  9 #include <cstring>
 10 #include <iostream>
 11 #include <algorithm>
 12 #include <map>
 13 #include <set>
 14 #include <vector>
 15 using namespace std;
 16
 17 int main(void)
 18 {
 19     //freopen ("C.in", "r", stdin);
 20
 21     set<string> s;
 22     string tmp;
 23     int n, m, mx;
 24
 25     while (cin >> n >> m)
 26     {
 27         mx = -1;
 28         s.clear ();
 29         for (int i=1; i<=n; ++i)
 30         {
 31             cin >> tmp;
 32             s.insert (tmp);
 33             int len = tmp.size ();
 34             mx = max (mx, len);
 35         }
 36         if (n * m * mx < 1e8)
 37         {
 38             for (int j=1; j<=m; ++j)
 39             {
 40                 cin >> tmp;
 41                 int cnt = 0;
 42                 set<string>::iterator it;
 43                 for (it=s.begin (); it!=s.end (); ++it)
 44                 {
 45                     if (it->size () == tmp.size ())
 46                     {
 47                         cnt = 0;
 48                         for (int j=0; j<it->size (); ++j)
 49                         {
 50                             if ((*it)[j] != tmp[j])   cnt++;
 51                             if (cnt > 1)    break;
 52                         }
 53                         if (cnt == 1)   break;
 54                     }
 55                 }
 56                 if (cnt == 1)   cout << "YES" << endl;
 57                 else    cout << "NO" << endl;
 58             }
 59             continue;
 60         }
 61
 62         for (int i=1; i<=m; ++i)
 63         {
 64             cin >> tmp;
 65             bool flag = false;
 66             for (int j=0; tmp[j]!='\0'; ++j)
 67             {
 68                 if (tmp[j] == 'a')
 69                 {
 70                     tmp[j] = 'b';
 71                     if (s.find (tmp) != s.end ())
 72                     {
 73                         flag = true;    break;
 74                     }
 75                     tmp[j] = 'c';
 76                     if (s.find (tmp) != s.end ())
 77                     {
 78                         flag = true;    break;
 79                     }
 80                     tmp[j] = 'a';
 81                 }
 82                 if (tmp[j] == 'b')
 83                 {
 84                     tmp[j] = 'a';
 85                     if (s.find (tmp) != s.end ())
 86                     {
 87                         flag = true;    break;
 88                     }
 89                     tmp[j] = 'c';
 90                     if (s.find (tmp) != s.end ())
 91                     {
 92                         flag = true;    break;
 93                     }
 94                     tmp[j] = 'b';
 95                 }
 96                 if (tmp[j] == 'c')
 97                 {
 98                     tmp[j] = 'a';
 99                     if (s.find (tmp) != s.end ())
100                     {
101                         flag = true;    break;
102                     }
103                     tmp[j] = 'b';
104                     if (s.find (tmp) != s.end ())
105                     {
106                         flag = true;    break;
107                     }
108                     tmp[j] = 'c';
109                 }
110             }
111             (flag) ? cout << "YES" << endl : cout << "NO" << endl;
112         }
113     }
114
115     return 0;
116 }
117
118 /*
119 YES NO
120 */