235 Lowest Common Ancestor of a Binary Search Tree

题目 235 Lowest Common Ancestor of a Binary Search Tree

因为是binary search tree,因此利用没个节点的值进行二分查找即可复杂度O(h)

class Solution:# @param {TreeNode} root# @param {TreeNode} p# @param {TreeNode} q# @return {TreeNode}def lowestCommonAncestor(self, root, p, q):if p.val > q.val:p,q = q,pif root.val in [p.val, q.val]:return rootif p.val < root.val < q.val:return rootelif p.val < root.val and q.val < root.val:return self.lowestCommonAncestor(root.left, p, q)else:return self.lowestCommonAncestor(root.right, p, q)

转载于:https://www.cnblogs.com/dapanshe/p/4641982.html

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