LeetCode 之Two Sum

问题要求

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].解题思路：考虑使用hashmap，将答案存于一个二维数组当中，遍历数组，将数组中的每个值与他对应的下标存储在hashmap中，直至找到一个数与前面的某一个数的和为target，找到这两个数对应的下标，存在二维数组当中。

public class Solution {public int[] twoSum(int[] nums, int target) {int []result = new int[2]  ;Map<Integer, Integer> map= new HashMap<Integer, Integer>();for(int i=0;i<nums.length;i++){if(map.containsKey(target-nums[i])){result[1]=i;result[0]=map.get(target-nums[i]);return result;}map.put(nums[i], i);}return result;}
}

转载于:https://www.cnblogs.com/mozhuyazhi/p/6535883.html

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