c++第八周【任务1-2】实现复数类中的运算符重载

/* (程序头部注释开始)
* 程序的版权和版本声明部分
* Copyright (c) 2011, 烟台大学计算机学院学生
* All rights reserved.
* 文件名称：   c++第八周【任务1-2】
* 作    者： 李洪悬
* 完成日期：   2012      年   4    月   11     日
* 版 本 号：
* 对任务及求解方法的描述部分
* 输入描述：
* 问题描述：实现复数类中的运算符重载
* 程序输出：
* 程序头部的注释结束
*/

任务1】实现复数类中的运算符重载
定义一个复数类重载运算符+、-、*、/，使之能用于复数的加减乘除。
（1）方案一：请用类的成员函数完成运算符的重载；
class Complex
{
public:
Complex(){real=0;imag=0;}
Complex(double r,double i){real=r;imag=i;}
Complex operator+(Complex &c2);
Complex operator-(Complex &c2);
Complex operator*(Complex &c2);
Complex operator/(Complex &c2);
void display();
private:
double real;
double imag;
};
//下面定义成员函数
int main()
{
Complex c1(3,4),c2(5,-10),c3;
cout<<"c1=";
c1.display();
cout<<"c2=";
c2.display();
c3=c1+c2;
cout<<"c1+c2=";
c3.display();
c3=c1-c2;
cout<<"c1-c2=";
c3.display();
c3=c1*c2;
cout<<"c1*c2=";
c3.display();
c3=c1/c2;
cout<<"c1/c2=";
c3.display();
system("pause");
return 0;
}
（2）方案二：请用类的友元函数，而不是成员函数，完成上面提及的运算符的重载；
（3）方案三：在方案二的基础上，扩展+、-、*、/运算符的功能，使之能与double型数据进行运算。设Complex c; double d; c?d和d?c的结果为将d视为实部为d的复数同c运算的结果（其中?为+、-、*、/之一）。另外，定义一目运算符-，-c相当于0-c。

#include < iostream >
using namespace std;
class Complex
{
public:
Complex()
{
real=0;
imag=0;
}
Complex (double r,double i)
{
real=r;
imag=i;
}
friend Complex operator + (Complex &c1 , Complex &c2);
friend Complex operator - (Complex &c1 , Complex &c2);
friend Complex operator * (Complex &c1 , Complex &c2);
friend Complex operator / (Complex &c1 , Complex &c2);
void display();
private:
double real;
double imag;
};
//复数相加:  (a+bi)+(c+di)=(a+c)+(b+d)i.
Complex operator + (Complex &c1 , Complex &c2)
{
Complex c;
c.real = c1.real + c2.real;
c.imag =c1.imag + c2.imag;
return c;
}
//复数相减:(a+bi)-(c+di)=(a-c)+(b-d)i.
Complex operator - (Complex &c1 , Complex &c2)
{
Complex c;
c.real = c1.real - c2.real;
c.imag = c1.imag - c2.imag;
return c;
}
//复数相乘:(a+bi)(c+di)=(ac－bd)+(bc+ad)i.
Complex operator * (Complex &c1 , Complex &c2)
{
Complex c;
c.real = c1.real * c2.real - c1.imag * c2.imag;
c.imag = c1.imag * c2.real + c1.real * c2.imag;
return c;
}
//复数相除:(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)i
Complex operator / (Complex &c1 , Complex  &c2)
{
Complex c;
c.real = (c1.real * c2.real + c1.imag * c2.imag) / (c2.real * c2.real + c2.imag * c2.imag);
c.imag = (c1.imag * c2.real - c1.real * c2.imag) / (c2.real * c2.real + c2.imag * c2.imag);
return c;
}
void Complex::display()
{
cout << "(" << real << " , " << imag << "i)" << endl;
}
int main()
{
Complex c1(3 , 4),c2(5 , -10),c3;
cout << " c1 = ";
c1.display();
cout << " c2 = ";
c2.display();
c3 = c1 + c2;
cout << " c1 + c2 = ";
c3.display();
c3 = c1 - c2;
cout << " c1 - c2 = ";
c3.display();
c3 = c1 * c2;
cout << " c1 * c2 = ";
c3.display ();
c3 = c1 / c2;
cout << " c1 / c2 = ";
c3.display ();
system ( " pause " );
return 0;
}

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