JAVA删除字符串固定下标的字串

当你拿到的报文是这样的

{"input": {"sdfsn": "23u4209350-2","fsfs": "128412094","sgsgsg": "15821059","inssgsuplc_admdfdfdvs": "125125332","dgh": "125215312","dfgdfg": "215215","sdhdsh": "","sdfsn": "","shdfshdshdsh": "shsdh","sdhdsh": "shsh.0","shsdhsd": "1","shsdh": "1607","input": {"data": {"dhfsdhsd": "235325","shsdhsdh": "03","dgd": "BE0445360","dfhfdh": "11","dshshsd": 76.56,"ghjrfgj": "01","grjf": "234623626","hjfd": "236436","djfdfgjdfj": "45634","exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}","dfjgdfj": "","dfjdfjgdfj": "56745745","dfgjdfgjh": 45756758,"jdfgjhfdgj": 0,}}},"output": {"output": {"r757": {"dhfsdhsd": "235325","shsdhsdh": "03","dgd": "BE0445360","dfhfdh": "11","dshshsd": 76.56,"ghjrfgj": "01","grjf": "234623626","hjfd": "236436","djfdfgjdfj": "45634","exp_content": "","dfjgdfj": "","dfjdfjgdfj": "56745745","dfgjdfgjh": 45756758,"jdfgjhfdgj": 0,},"sdfgsdfg": [{"sgasgag": "4673476","agasgdas": 5675467,"asgasgasg": "","asdgasgas": 4567456754,"dhsdsxchsdh": 54675467,"sdfhsdhsdh": "5674756457"}]},"erherth": 0,}
}

这一看就知道上边的报文在postman里边肯定会报错，因为exp_Content，因此他又没有用到，所以你想把他删掉。其实也没那么难删

也就是用到了流转字符串。字符串固定字符查找，然后进行字符串转字符流，删掉字符流中固定字符，之后再转回来。因为字符串已经是final了所以很多用法都是使用字符串转字符流实现的

实现代码如下

    private JSONObject resolveApplicationJson(HttpServletRequest request) {InputStream is = null;String json = null;try {is = request.getInputStream();json = IOUtils.toString(is, "UTF-8");json=json.replaceAll("\\r|\n|\t","");int index=  json.indexOf("exp_Content");int indexfirst=json.indexOf("{", index);int indexlast=json.indexOf("}",index);if (index!=-1 && indexlast !=-1 &&indexfirst !=-1) {StringBuffer stringBuffer = new StringBuffer(json);stringBuffer.delete(indexfirst,indexlast+1);json=stringBuffer.toString();}} catch (IOException e) {throw new RuntimeException("CANNOT get reader from request!", e);   } finally {if (is != null) {try {is.close();} catch (IOException e) {e.printStackTrace();}}}try {return new JSONObject(json);} catch (JSONException e) {throw new RuntimeException("CANOT CONVET JSON:[" + json + "] to JSONObject!", e);}}

搞定。

多存在多个不符合规定的数据然后你要删掉怎么操作呢？
这也很简单，如果你看了这一篇文章，你要更好的解决方式，期待一起探讨，学习进步(＾－＾)V

你拿到的报文是这样的。

{"input": {"sdfsn": "23u4209350-2","fsfs": "128412094","sgsgsg": "15821059","inssgsuplc_admdfdfdvs": "125125332","dgh": "125215312","dfgdfg": "215215","sdhdsh": "","sdfsn": "","shdfshdshdsh": "shsdh","sdhdsh": "shsh.0","shsdhsd": "1","shsdh": "1607","input": {"data": {"dhfsdhsd": "235325","shsdhsdh": "03","dgd": "BE0445360","dfhfdh": "11","dshshsd": 76.56,"ghjrfgj": "01","grjf": "234623626","hjfd": "236436","djfdfgjdfj": "45634","exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}","dfjgdfj": "","dfjdfjgdfj": "56745745","dfgjdfgjh": 45756758,"jdfgjhfdgj": 0,}}},"output": {"output": {"r757": {"dhfsdhsd": "235325","shsdhsdh": "03","dgd": "BE0445360","exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}","dfhfdh": "11","dshshsd": 76.56,"ghjrfgj": "01","grjf": "234623626","hjfd": "236436","djfdfgjdfj": "45634","exp_content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}","dfjgdfj": "","dfjdfjgdfj": "56745745","dfgjdfgjh": 45756758,"jdfgjhfdgj": 0,},"sdfgsdfg": [{"sgasgag": "4673476","agasgdas": 5675467,"asgasgasg": "","asdgasgas": 4567456754,"dhsdsxchsdh": 54675467,"sdfhsdhsdh": "5674756457"}]},"erherth": 0,}
}

解决方式如下，先使用正则看看有几个这样的不需要的符号，然后循环遍历几次，然后找到这部分，然后删除掉。
实现代码如下

# 全局变量
private static String REGEX = "exp_[c,C]ontent";# 方式方法
Pattern p = Pattern.compile(REGEX);// 获取 matcher 对象Matcher m = p.matcher(JSON);List<Integer> list = new ArrayList();while(m.find()){list.add(m.start());}int index=0;int indexfirst=0;int indexlast=0;for (int j = 0; j < list.size(); j++) {index=JSON.indexOf("exp_",indexlast);indexfirst=JSON.indexOf("{", index);indexlast=JSON.indexOf("}",index);StringBuffer stringBuffer =null;if (indexlast !=-1 &&indexfirst !=-1) {stringBuffer = new StringBuffer(JSON);stringBuffer.delete(indexfirst,indexlast+1);}JSON=stringBuffer.toString();}

end》》》
问题 = 机会。遇到问题的时候，内心其实是开心的，越大的问题意味着越大的机会。

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