leetcode- Single Number

2019独角兽企业重金招聘Python工程师标准>>>

Given an array of integers, every element appears twice except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

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class Solution {
public:int singleNumber(vector<int>& nums) {int len=nums.size();int res = 0;for(int i=0; i<len; i++){res = res^nums[i];}return res;}
};

转载于:https://my.oschina.net/u/2368952/blog/527541

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