工作中用到的sql

selectt."ID",t."TITLE",t."SENDUSERID",t."SENDTIME",t."URL",t."USERID",t."TODOTYPE",t."MODELNAME",t."IMPORTANCE",t."SENDUSERNAME",t."SENDUSERDEPTNAME",t.DATAID,t.OPENFLAG,t.realuserid,t.status,t.donetime from
(select m."ID",m."TITLE",m."SENDUSERID",m."SENDTIME",m."URL",m."USERID",m."TODOTYPE",m."MODELNAME",m."IMPORTANCE",m."SENDUSERNAME",m."SENDUSERDEPTNAME",m.DATAID,m.OPENFLAG,m.realuserid,m.status,m.donetime , row_number() over(partition by m.DATAID,m.status,m.realuserid order by m."SENDTIME" desc) rn from (
select a."ID",a."TITLE",a."SENDUSERID",a."SENDTIME",a."URL",a."USERID",a."TODOTYPE",a."MODELNAME",a."IMPORTANCE",a."SENDUSERNAME",a."SENDUSERDEPTNAME",a.DATAID,b.OPENFLAG,b.userid as realuserid,b.status,b.donetimefrom TD_HORIZON_Info a, TD_HORIZON_User bwhere a.id = b.TODOID) m )twhere rn=1;

  场景：查询出每个部门工资最低的员工编号【每个部门可能有两个最低的工资员工】

--row_number() 顺序排序
select row_number() over(partition by deptid order by salary) my_rank ,deptid,USERID,salary from tsaler;
--rank() （跳跃排序，如果有两个第一级别时，接下来是第三级别）
select rank() over(partition by deptid order by salary) my_rank,deptid,USERID,salary from tsaler;
--dense_rank（）（连续排序，如果有两个第一级别时，接下来是第二级）
select dense_rank() over(partition by deptid order by salary) my_rank,deptid,USERID,salary from tsaler;
-------方案3解决方案
select * from (select rank() over(partition by deptid order by salary) my_rank,deptid,USERID,salary from tsaler) where my_rank=1;
select * from (select dense_rank() over(partition by deptid order by salary) my_rank,deptid,USERID,salary from tsaler) where my_rank=1;