Type string trivially inferred from a string literal, remove type annotation.eslint@typescript-eslin

TypeScript代码类似：

const web: string = "Hello World";

如果是用eslint 验证会导致报错

Type string trivially inferred from a string literal, remove type annotation.eslint@typescript-eslint/no-inferrable-types

从字符串文字中简单推断出字符串类型，删除类型注释。eslint @ typescript-eslint / no-inferrable-types
他觉得已经推断出是字符串类型，不需要写了
解决办法：
.eslintrc.js 里面加上

rules: {"@typescript-eslint/no-inferrable-types": "off" // 关闭类型推断
}

如果是用tslint 验证会导致报错

Type string trivially inferred from a string literal, remove type annotation (no-inferrable-types)。

解决办法：
tslint.json 里面添加"ignore-properties"。

"no-inferrable-types": [true,"ignore-params","ignore-properties"
],

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