我把浮点数的格式改为小数点后1位。data = {'A Prime': {0: 3.26, 1: 3.24, 2: 3.22, 3: 3.2, 4: 3.18, 5: 3.16,

6: 3.14, 7: 1.52, 8: 1.5, 9: 1.48, 10: 1.46, 11: 1.44, 12: 1.42},

'B': {0: 0.16608, 1: 0.16575, 2: 0.1654, 3: 0.16505999999999998, 4: 0.1647, 5: 0.16434, 6: 0.16398, 7: 0.10759, 8: 0.10687, 9: 0.10614000000000001,

10: 0.10540999999999999, 11: 0.10469, 12: 0.10396}, 'Proto Name': {0: 'Alpha',

1: 'Alpha', 2: 'Alpha', 3: 'Alpha', 4: 'Alpha', 5: 'Alpha', 6: 'Alpha', 7: 'Bravo', 8: 'Bravo', 9: 'Bravo', 10: 'Bravo', 11: 'Bravo', 12: 'Bravo'}}

import pandas as pd

df = pd.DataFrame(data)

A Prime B Proto Name

0 3.26 0.16608 Alpha

1 3.24 0.16575 Alpha

2 3.22 0.16540 Alpha

3 3.20 0.16506 Alpha

4 3.18 0.16470 Alpha

5 3.16 0.16434 Alpha

6 3.14 0.16398 Alpha

7 1.52 0.10759 Bravo

8 1.50 0.10687 Bravo

9 1.48 0.10614 Bravo

10 1.46 0.10541 Bravo

11 1.44 0.10469 Bravo

12 1.42 0.10396 Bravo

writer = pd.ExcelWriter(r'c:\temp\output.xlsx')

# This method will truncate the data past the first decimal point

df.to_excel(writer,'Sheet1',float_format = "%0.1f")

writer.save()

但是，唉，也许不是所有的情况-说大数字和千位分隔符没有乐趣df.to_excel(writer,'Sheet1',float_format = ":,")

不过，下面的方法似乎有效data = {'A Prime': {0: 326000, 1: 3240000}}

df = pd.DataFrame(data)

A Prime

0 326000

1 3240000

writer = pd.ExcelWriter(r'c:\temp\output.xlsx')

df.to_excel(writer,'Sheet1')

workbook = writer.book

worksheet = writer.sheets['Sheet1']

format1 = workbook.add_format({'num_format': '#,##0.00'})

worksheet.set_column('B', 18, format1)

#Alternatively, you could specify a range of columns with 'B:D' and 18 sets the column width

writer.save()