(以下代码中都只做测试用,有些地方没有释放内存...这个自己解决下)

1.RSA非对称的,首先提供一个供测试用的证书和私钥的数据

1)pem格式的证书和私钥(公私钥是对应的)的base64编码

void readPriKey(string &a){
a =  "-----BEGIN RSA PRIVATE KEY-----\n";
a.append("MIICXQIBAAKBgQDTFPiHkUX279j7OnK2ToLrwD/QI9N/fL/XoMnW1sBYJdSWs/VP\n");
a.append("5oywvy6yJ0KMpfYcbRCJh2oRbPw7T9IrSHKdOkhB9PF6qwn90xb3Bk22l1LYZNfw\n");
a.append("IQKqRjAXctR8GSC5ULBQmZK2T6m50oD5vl6rD6lnmrQyQSZ3tNNRYbxx/QIDAQAB\n");
a.append("AoGAVqzSzOAzaY3dfHPorMGacvHzgiVj8IKqSAHHP8fZHZkTLXrh7ZhPBzjKFO+Y\n");
a.append("HSb843lJhB+tx1AIVtaVB57tKLHJSrAjFem6mHV+X+JhMeX358QS0QFbUiKfAK5e\n");
a.append("AkM1UdihF/3BX47DZUe44ntRqhffwsNGuZs2tB5FPHIpnGUCQQDvuBumamo+4tff\n");
a.append("oF9Z/iuMJTyDerPgrQbC85ZoHBULLKtnzSUt7pdSsPMMBfImDpquhkLntC+kFV5b\n");
a.append("yXu2nC5bAkEA4Wr1na+izFxmOnppvOjs7eFnch2THvNsajJ+Yl/jnRGGS5CLccrd\n");
a.append("JgUm+j91VUitl88XY/GXAUDIobGw/iAAhwJBANZziODekD/D5cVcDhFPDZwpb7Jb\n");
a.append("ofHcOJFNIv/uJ3FAu/J3lsw5hsxmGnhmFVOwevaoi9AG5RvQNgK9A9zAacMCQQDT\n");
a.append("PI4qVHp0k2nhBvGra4MLcBymXXyOloJUCjlRKpZ7i/6TNULXQcl3ZYCfJXRolRDH\n");
a.append("n/NFXxGoxPK+Q2ue2JJlAkBw1Z/1q2f6JYJ8pLBvdBSmOmKvm+O7x5s0csN7DnXf\n");
a.append("aK1D4/cyCbLdqgogbolQkOwIwUuXLkitW1ldh+MinTMz\n");
a.append("-----END RSA PRIVATE KEY-----\n");
}
void readCert(string &a){
a = "-----BEGIN CERTIFICATE-----\n";
a.append("MIIGVTCCBT2gAwIBAgIKGCyzsAAAAAAAbjANBgkqhkiG9w0BAQUFADA9MRUwEwYK\n");
a.append("CZImiZPyLGQBGRYFbG9jYWwxEzARBgoJkiaJk/IsZAEZFgNpc3MxDzANBgNVBAMT\n");
a.append("BldIVUlTUzAeFw0xMjA0MTEwMTMxNThaFw0xMzA0MTEwMTMxNThaMHIxFTATBgoJ\n");
a.append("kiaJk/IsZAEZFgVsb2NhbDETMBEGCgmSJomT8ixkARkWA2lzczEOMAwGA1UEAxMF\n");
a.append("VXNlcnMxEjAQBgNVBAMMCeWRqOe7jeemuTEgMB4GCSqGSIb3DQEJARYRemhvdXl1\n");
a.append("emh5QDEyNi5jb20wgZ8wDQYJKoZIhvcNAQEBBQADgY0AMIGJAoGBANMU+IeRRfbv\n");
a.append("2Ps6crZOguvAP9Aj0398v9egydbWwFgl1Jaz9U/mjLC/LrInQoyl9hxtEImHahFs\n");
a.append("/DtP0itIcp06SEH08XqrCf3TFvcGTbaXUthk1/AhAqpGMBdy1HwZILlQsFCZkrZP\n");
a.append("qbnSgPm+XqsPqWeatDJBJne001FhvHH9AgMBAAGjggOkMIIDoDAdBgNVHQ4EFgQU\n");
a.append("vjfBpRVvsUsaWnX4dC81QzXu5T4wHwYDVR0jBBgwFoAU++PzmmgpwxErxTVrbJp5\n");
a.append("IzqO3RswggECBgNVHR8EgfowgfcwgfSggfGgge6GgbNsZGFwOi8vL0NOPVdIVUlT\n");
a.append("UyxDTj16c3ktMDIxMWMxNWEyNTIsQ049Q0RQLENOPVB1YmxpYyUyMEtleSUyMFNl\n");
a.append("cnZpY2VzLENOPVNlcnZpY2VzLENOPUNvbmZpZ3VyYXRpb24sREM9aXNzLERDPWxv\n");
a.append("Y2FsP2NlcnRpZmljYXRlUmV2b2NhdGlvbkxpc3Q/YmFzZT9vYmplY3RDbGFzcz1j\n");
a.append("UkxEaXN0cmlidXRpb25Qb2ludIY2aHR0cDovL3pzeS0wMjExYzE1YTI1Mi5pc3Mu\n");
a.append("bG9jYWwvQ2VydEVucm9sbC9XSFVJU1MuY3JsMIIBFgYIKwYBBQUHAQEEggEIMIIB\n");
a.append("BDCBowYIKwYBBQUHMAKGgZZsZGFwOi8vL0NOPVdIVUlTUyxDTj1BSUEsQ049UHVi\n");
a.append("bGljJTIwS2V5JTIwU2VydmljZXMsQ049U2VydmljZXMsQ049Q29uZmlndXJhdGlv\n");
a.append("bixEQz1pc3MsREM9bG9jYWw/Y0FDZXJ0aWZpY2F0ZT9iYXNlP29iamVjdENsYXNz\n");
a.append("PWNlcnRpZmljYXRpb25BdXRob3JpdHkwXAYIKwYBBQUHMAKGUGh0dHA6Ly96c3kt\n");
a.append("MDIxMWMxNWEyNTIuaXNzLmxvY2FsL0NlcnRFbnJvbGwvenN5LTAyMTFjMTVhMjUy\n");
a.append("Lmlzcy5sb2NhbF9XSFVJU1MuY3J0MAwGA1UdEwEB/wQCMAAwCwYDVR0PBAQDAgWg\n");
a.append("MD4GCSsGAQQBgjcVBwQxMC8GJysGAQQBgjcVCIbd/wqC4JYWgbmLGoKIvT+HxNMh\n");
a.append("gXGE+cJBg4yVdgIBZAIBBjApBgNVHSUEIjAgBggrBgEFBQcDAgYIKwYBBQUHAwQG\n");
a.append("CisGAQQBgjcKAwQwNQYJKwYBBAGCNxUKBCgwJjAKBggrBgEFBQcDAjAKBggrBgEF\n");
a.append("BQcDBDAMBgorBgEEAYI3CgMEMDsGA1UdEQQ0MDKgHQYKKwYBBAGCNxQCA6APDA16\n");
a.append("c3lAaXNzLmxvY2FsgRF6aG91eXV6aHlAMTI2LmNvbTBEBgkqhkiG9w0BCQ8ENzA1\n");
a.append("MA4GCCqGSIb3DQMCAgIAgDAOBggqhkiG9w0DBAICAIAwBwYFKw4DAgcwCgYIKoZI\n");
a.append("hvcNAwcwDQYJKoZIhvcNAQEFBQADggEBABj0xXhayI5JdqbuyAbqNwzGZxt4X102\n");
a.append("CFFeTU5jauspQjqEpar+/IQ+r3/vf162bY/lLHLpDarFLbZ9dAC6nqNfnE4gg9r7\n");
a.append("p+dbkbzFyBuSTqrzHQ6JgRYSdjwaksHV+uZuP7dfP2HXw4F1T3Ch/7ZKW9+ZlVvd\n");
a.append("QCygAu0z+TS2e7oRFb+swQLVKda8kPTM/b69+r/xdTHXY6+CkfVAk4oYBB56a9AD\n");
a.append("t1XOoAUa42fJdit6+7ssLLTZkZLNsQl6qsuTdv64dIMda4C6NnUsKDfjWGa+0vs3\n");
a.append("VjVNsUC5jo4qRc4XmBvJIx6e5M420sPj2Gi/+ssgmaXK+zUWzowIoMU=\n");
a.append("-----END CERTIFICATE-----\n");
}

2)CryptoAPI和openssl公私钥保持一致,去掉pem头尾直接用便是,没有加密

证书的:

void readCertBase64(string &a){
a = "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\n";
}

因为尝试私钥没有导入成功,暂且不管,关于这一点待会再说验证交互成功的替换方案

2.先来看下openssl的RSA实现方案,openssl本身提供了许多的padding方式,

因为CryptoAPI只提供了PKCS1和OAEP两种补齐方式,默认使用的PKCS1,那这里就用PKCS1来验证吧

1)首先需要导入证书和私钥,用于后续加密解密,这里就直接采用通过Base64码来导入

EVP_PKEY * importKey(){
OpenSSL_add_all_algorithms();
EVP_PKEY *prikey;
string a = "";
readPriKey(a);//获取私钥的base64码
const char* sPriKey = a.c_str();
BIO* bio = BIO_new_mem_buf((void*)sPriKey,strlen(sPriKey));//通过BIO放入内存
prikey = PEM_read_bio_PrivateKey(bio,NULL,NULL,NULL);//读取bio,获取私钥对象
BYTE* sign_value = (BYTE*)malloc(1024);
unsigned int len;
return prikey;
}
EVP_PKEY * importCert(){
X509* cert;
OpenSSL_add_all_algorithms();
string a = "";
readCert(a);//证书的base64码
const char* sCert = a.c_str();
BIO* bio = BIO_new_mem_buf((void*)sCert,strlen(sCert));//存到内存
cert = PEM_read_bio_X509(bio,NULL,NULL,NULL);//读取bio,获取证书对象
EVP_PKEY* evp_pubKey =X509_get_pubkey(cert);//获取证书的公钥
int len;
if(evp_pubKey){
return evp_pubKey;
}
else
cout << "evp_pubKey == NULL" << endl;
return NULL;
}

2)有了公钥,私钥对象,接下来做非对称加密和解密就简单些了

这里得提下补齐方式,因为和CryptoAPI的补齐方式要保持一致,折腾了许多时间

CryptoAPI的默认补齐方式是PKCS1,我先以为就是NO_PADDING,结果发现CryptoAPI貌似就没有对NO_PADDING的支持

openssl有NO_PADDING的支持,如果使用这个方式,最好自己将剩余位全部补上规律的数据,便于解密后容易获取到要的明文

NO_PADDING就必须明文和密钥大小一样了,1024位RSA对应128字节明文

PKCS1的得减去11字节存储PKCS1自己的数据,1024位RSA只能加密117字节明文

OAEP则得减去41字节,只能加密87字节明文

如果超过大小,当然可以自己去分节处理,这里就不予讨论了

void evelop(EVP_PKEY* evp_pubKey/*公钥对象*/,BYTE** out/*加密结果*/,unsigned int &cOut/*加密结果大小*/,const BYTE* in/*明文*/,unsigned int cIn/*明文大小*/){
OpenSSL_add_all_algorithms();
bool hasErr = true;
EVP_PKEY_CTX* ctx = EVP_PKEY_CTX_new(evp_pubKey,NULL);
if(!ctx)
goto err;
if(EVP_PKEY_encrypt_init(ctx)<=0)
goto err;
if (EVP_PKEY_CTX_set_rsa_padding(ctx, RSA_PKCS1_PADDING) <= 0)//设置补齐方式
goto err;
if(EVP_PKEY_encrypt(ctx,NULL,&cOut,in,cIn)<=0)//得到加密的长度,一般都是跟密钥一样长,1024位的RSA密钥就是128字节
goto err;
*out =(BYTE*) OPENSSL_malloc(cOut);
if(!out)
goto err;
if(EVP_PKEY_encrypt(ctx,*out,&cOut,in,cIn)<=0)//得到加密结果
goto err;
cout << "加密成功!" << endl;
hasErr = false;
err:
EVP_PKEY_CTX_free(ctx);
if(!hasErr)
return;
return;
}
void develop(EVP_PKEY* priKey,BYTE** out,unsigned int &cOut, BYTE* data,unsigned int cData){
OpenSSL_add_all_algorithms();
bool hasErr = true;
EVP_PKEY_CTX* ctx = EVP_PKEY_CTX_new(priKey,NULL);
if(!ctx)
goto err;
if (EVP_PKEY_decrypt_init(ctx) <= 0)
goto err;
if(EVP_PKEY_CTX_set_rsa_padding(ctx, RSA_PKCS1_PADDING) <= 0)//与加密同样的PKCS1补齐
goto err;
if (EVP_PKEY_decrypt(ctx, NULL, &cOut, data, cData) <= 0)//解密结果大小
goto err;
*out =(BYTE*) OPENSSL_malloc(cOut);//分配内存
if (!out)
goto err;
if (EVP_PKEY_decrypt(ctx, *out, &cOut, data, cData) <= 0)//得到解密结果
goto err;
hasErr = false;
err://输出一些错误信息,偶尔错误信息得不到,只得到一些文件名和所在行,就跑到源代码去找...麻烦死了,如果有好的方案求回复~
EVP_PKEY_CTX_free(ctx);
if(!hasErr)
return;
cout << "err in develop" << endl;
const      char*file,*data1,*efunc,*elib,*ereason,*p;
int                         line,flags;
unsigned long  errn;
errn=ERR_peek_error_line_data(&file,&line,&data1,&flags);
printf("ERR_peek_error_line_data err : %ld,file :%s,line :%d,data :%s\n",errn,file,line,data1);
}

3)自己测试下上面的代码吧,应该是没问题的

2.CryptoAPI的RSA非对称加密

1)首先依然是公私钥数据问题

这里先看下通过base64导入证书吧,私钥的问题放在第三部分再讨论

PCCERT_CONTEXT  importCryptoCert(string base64Cert){
PCCERT_CONTEXT  pCertContext = NULL;
int len;
BYTE* certEncoded = Base64::base64_decode(base64Cert,len);//BASE64解码,很多方式,先前博文中有代码
if(pCertContext = CertCreateCertificateContext(
X509_ASN_ENCODING | PKCS_7_ASN_ENCODING,
certEncoded,
len)) //直接就通过字节数组导入成证书上下文对象了
{
printf("A new certificate has been created.\n");
}
else
{
printf("A new certificate could not be created.\n");
}
return pCertContext;
}

2)公钥加密,CryptoAPI的公钥加密也做了一些封装,没注意到的话得折腾好长时间

我使用的CryptEncrypt,而加密结果是以 little-endian  排列的字节数组,openssl则与其相反

关于CryptoAPI的说明,remark最后一句话,很小的字....

void encryptByPubKey(HCRYPTPROV hProv,PCCERT_CONTEXT cert,BYTE* text,unsigned long &len){
HCRYPTKEY hKey;
CERT_PUBLIC_KEY_INFO pubKeyInfo = cert->pCertInfo->SubjectPublicKeyInfo;//拿到公钥信息
if(!CryptImportPublicKeyInfoEx(hProv,X509_ASN_ENCODING,&pubKeyInfo,CALG_RSA_KEYX,0,NULL,&hKey))//导入,获取公钥对象
{
printf("CryptImportPublicKeyInfoEx error:0X%x.\n",GetLastError());
return;
}
if(!CryptEncrypt(hKey,NULL,true,0,text,&len,128))//加密,padding参数为0,默认就是PKCS1的,不用管了,最后一个参数为128,是对于1024位RSA密钥,明文text得分配128个字节
{
printf("CryptEncrypt error:0X%x.\n",GetLastError());
return;
}
//以下将密文倒序,如果你在openssl倒序了,那这里就不用了,反正CryptoAPI和openssl本身的排列方式就是反的
for(int i = 0 ; i < len / 2;i++)
{
BYTE temp = text[i];
text[i] = text[len - i - 1];
text[len - i - 1] = temp;
}
printByte(text,len);
}

3)试下这个部分的加密吧,能够被openssl解密就没问题了

3.以上只试了CryptoAPI加密openssl解密,因为私钥没导入成功的关系,也没时间再去尝试了,暂且换一种替代方案来测试

如果CryptoAPI解密了CryptoAPI加密的,那这个也是等价的,那干脆直接从windows密钥库获取公私钥,用CryptoAPI直接做加密解密

从windows库获取证书就不在这讨论了,看下私钥解密的部分

void decryptByPriKey(PCCERT_CONTEXT cert,BYTE* encText,unsigned long len){
//将结果再反序一次,用于CryptoAPI自己解密
for(int i = 0 ; i < len / 2;i++)
{
BYTE temp = encText[i];
encText[i] = encText[len - i - 1];
encText[len - i - 1] = temp;
}
HCRYPTPROV_OR_NCRYPT_KEY_HANDLE hKeyProv;
DWORD *dwKeyType;
BOOL bFreeKeyProv = FALSE;
if(!CryptAcquireCertificatePrivateKey(cert, 0, 0, &hKeyProv, dwKeyType, &bFreeKeyProv))  //获取证书对应的私钥句柄
{
printf("CryptAcquireCertificatePrivateKey error:0X%x.\n",GetLastError());
return;
}
HCRYPTKEY hKey;
if(!CryptGetUserKey(hKeyProv,AT_KEYEXCHANGE,&hKey))//通过句柄获取私钥对象
{
printf("CryptGetUserKey error:0X%x.\n",GetLastError());
return;
}
if(!CryptDecrypt(hKey,NULL,true,0,encText,&len)){//解密,也可以把padding参数换成CRYPT_DECRYPT_RSA_NO_PADDING_CHECK
printf("CryptDecrypt error:0X%x.\n",GetLastError());
return;
}
printByte(encText,len);
}

如果到此都没有什么问题,整个交互就算完成了.

前一篇提了AES的,还差一个签名的下回再来讨论了