复数中的运算符重载（续）

问题及代码：

/* * Copyright (c) 2014, 烟台大学计算机学院 * All rights reserved. * 文件名称：test.cpp * 作    者：李盈盈  * 完成日期：2015年 05 月 07 日 * 版 本 号：v1.0 * * 问题描述：定义一目运算符 -，-c相当于0-c，定义Complex类中的<<和>>运算符的重载，实现输入和输出。* 输入描述：输入各复数。* 程序输出：输出加减乘除后的结果。*/
#include <iostream>
using namespace std;
class Complex
{
public:Complex(){real=0;imag=0;}Complex(double r,double i){real=r;imag=i;}Complex operator-();//实现输入、输出的运算符重载friend ostream& operator << (ostream& output, const Complex& c);friend istream& operator >> (istream& input, Complex& c);//实现加减乘除的运算符重载friend Complex operator+(Complex &c1, Complex &c2);friend Complex operator+(double d1, Complex &c2);friend Complex operator+(Complex &c1, double d2);friend Complex operator-(Complex &c1, Complex &c2);friend Complex operator-(double d1, Complex &c2);friend Complex operator-(Complex &c1, double d2);friend Complex operator*(Complex &c1, Complex &c2);friend Complex operator*(double d1, Complex &c2);friend Complex operator*(Complex &c1, double d2);friend Complex operator/(Complex &c1, Complex &c2);friend Complex operator/(double d1, Complex &c2);friend Complex operator/(Complex &c1, double d2);
private:double real;double imag;
};
//实现输出的运算符重载
ostream& operator << (ostream& output, const Complex& c)
{output<<"("<<c.real;if(c.imag>=0) output<<"+";output<<c.imag<<"i)";return output;
}
//实现输入的运算符重载
istream& operator >> (istream& input, Complex& c)
{int a,b;char sign,i;do{cout<<"input a complex number(a+bi或a-bi):";input>>a>>sign>>b>>i;}while(!((sign=='+'||sign=='-')&&i=='i'));c.real=a;c.imag=(sign=='+')?b:-b;return input;
}
Complex Complex::operator-()
{return(0-*this);
}
//复数相加：(a+bi)+(c+di)=(a+c)+(b+d)i.
Complex operator+(Complex &c1, Complex &c2)
{Complex c;c.real=c1.real+c2.real;c.imag=c1.imag+c2.imag;return c;
}
Complex operator+(double d1, Complex &c2)
{Complex c(d1,0);return c+c2;
}
Complex operator+(Complex &c1, double d2)
{Complex c(d2,0);return c1+c;
}
//复数相减：(a+bi)-(c+di)=(a-c)+(b-d)i.
Complex operator-(Complex &c1, Complex &c2)
{Complex c;c.real=c1.real-c2.real;c.imag=c1.imag-c2.imag;return c;
}
Complex operator-(double d1, Complex &c2)
{Complex c(d1,0);return c-c2;
}
Complex operator-(Complex &c1, double d2)
{Complex c(d2,0);return c1-c;
}//复数相乘：(a+bi)(c+di)=(ac－bd)+(bc+ad)i.
Complex operator*(Complex &c1, Complex &c2)
{Complex c;c.real=c1.real*c2.real-c1.imag*c2.imag;c.imag=c1.imag*c2.real+c1.real*c2.imag;return c;
}
Complex operator*(double d1, Complex &c2)
{Complex c(d1,0);return c*c2;
}
Complex operator*(Complex &c1, double d2)
{Complex c(d2,0);return c1*c;
}//复数相除：(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)i
Complex operator/(Complex &c1, Complex &c2)
{Complex c;c.real=(c1.real*c2.real+c1.imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);c.imag=(c1.imag*c2.real-c1.real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);return c;
}
Complex operator/(double d1, Complex &c2)
{Complex c(d1,0);return c/c2;
}Complex operator/(Complex &c1, double d2)
{Complex c(d2,0);return c1/c;
}int main()
{Complex c1,c2,c3;double d=11;cout<<"c1: "<<endl;;cin>>c1;cout<<"c2: "<<endl;cin>>c2;cout<<"c1="<<c1<<endl;cout<<"c2="<<c2<<endl;cout<<"d="<<d<<endl;cout<<"-c1="<<(-c1)<<endl;c3=c1+c2;cout<<"c1+c2="<<c3<<endl;cout<<"c1+d="<<(c1+d)<<endl;cout<<"d+c1="<<(d+c1)<<endl;c3=c1-c2;cout<<"c1-c2="<<c3<<endl;cout<<"c1-d="<<(c1-d)<<endl;cout<<"d-c1="<<(d-c1)<<endl;c3=c1*c2;cout<<"c1*c2="<<c3<<endl;cout<<"c1*d="<<(c1*d)<<endl;cout<<"d*c1="<<(d*c1)<<endl;c3=c1/c2;cout<<"c1/c2="<<c3<<endl;cout<<"c1/d="<<(c1/d)<<endl;cout<<"d/c1="<<(d/c1)<<endl;return 0;
}

运行结果：

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