[Python] 纯文本查看 复制代码# -*- coding: utf-8 -*-

"""

Created on Fri Dec 18 22:53:40 2020

@author: ciker

"""

# -*- coding: utf-8 -*-

import xlrd

import docx

import datetime

def open_excel(file= '员工职级(岗级)汇总表.xls'):

try:

data = xlrd.open_workbook(file)

return data

except IOError:

print("ioerror")

#根据索引获取Excel表格中的数据 参数:file：Excel文件路径 colnameindex：表头列名所在行的所以 ，by_index：表的索引

def excel_table_byindex(file= '员工职级(岗级)汇总表.xls',colnameindex=2,by_index=0):

data = open_excel(file)

table = data.sheets()[by_index]

nrows = table.nrows #行数

colnames = table.row_values(colnameindex) #某一行数据

list =[]

for rownum in range(3,nrows):

row = table.row_values(rownum)

if row:

app = {}

for i in range(len(colnames)):

app[colnames[i]] = row[i]

list.append(app)

return list

def dateformat(day):

d1900 = datetime.datetime.strptime('1899-12-30', '%Y-%m-%d')

delta=datetime.timedelta(days=day)

n_days=d1900+delta

t1 = n_days.strftime('%Y-%m-%d ')

return t1

def main():

docname = ""

exceltables = excel_table_byindex()

doc = docx.Document('1.doc')

doctable = doc.tables[0]

doctable.style.font.name = '方正仿宋_GBK'

for row in exceltables:

doctable.cell(0,1).text = row['姓名']

doctable.cell(0,3).text = row['性别']

doctable.cell(0,6).text = dateformat(row['出生年月'])

doctable.cell(1,1).text = dateformat(row['工作时间'])

doctable.cell(1,3).text = row['最高学历']

doctable.cell(1,6).text = row['行政职务']

doctable.cell(2,1).text = str(int(row['技术资格']))

doctable.cell(2,3).text = str(int(row['技能等级']))

doctable.cell(2,6).text = row['现任岗位']

doctable.cell(4,1).text = row['申报岗位标准名称']

doctable.cell(6,1).text = row['企业管理序列/项目管理序列']

doctable.cell(6,3).text = str(row['职级'])

doctable.cell(6,6).text = row['岗位类别']

docname = str(int(row["序号"]))+row['姓名']+".doc"

doc.save(docname)

if __name__=="__main__":

main()