1058. A+B in Hogwarts (20)

时间限制

50 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 10⁷], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

解析:简单题,代码如下:

#include <stdio.h>typedef struct
{int ga;int si;int kn;
} num;void Plus(num *pA, num *pB)
{num C;C.ga = pA->ga + pB->ga;C.si = pA->si + pB->si;C.kn = pA->kn + pB->kn;C.si += C.kn / 29;C.kn = C.kn % 29;C.ga += C.si / 17;C.si = C.si % 17;printf("%d.%d.%d\n", C.ga, C.si, C.kn);
}int main()
{num A, B;scanf("%d.%d.%d%d.%d.%d", &A.ga, &A.si, &A.kn, &B.ga, &B.si, &B.kn);Plus(&A, &B);return 0;
}

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