A+B in Hogwarts (20)

水题

题目描述

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough."  Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

输入描述:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

输出描述:

For each test case you should output the sum of A and B in one line, with the same format as the input.

AC代码：

#include<bits/stdc++.h>
using namespace std;struct num{int a;int b=0;
}uni[10000];int main()
{int n,len=0;cin>>n;for(int i=0;i<n;i++){int num,pd=1;cin>>num;for(int j=0;j<len;j++ ){if(num==uni[j].a) {uni[j].b++;pd=0;break;}}if(pd) {uni[len].a=num;uni[len].b++;len++;}}int  x=1;for(int i=0;i<len;i++){if(uni[i].b==1) {cout<<uni[i].a;x=0;break;}}if(x) cout<<"None";return 0;
}

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A+B in Hogwarts (20)

题目描述

输入描述:

输出描述:

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