Given a binary tree, return all root-to-leaf paths.

For example, given the following binary tree:

   1/   \
2     3\
  5

All root-to-leaf paths are:

[“1->2->5”, “1->3”]

解题思路

先序遍历，递归的过程中保存路径，遇到叶子节点时将路径加入结果集。

实现代码

Java：

// Runtime: 3 ms
/*** Definition for a binary tree node.* public class TreeNode {*     int val;*     TreeNode left;*     TreeNode right;*     TreeNode(int x) { val = x; }* }*/
public class Solution {private List<String> paths = new ArrayList<String>();public List<String> binaryTreePaths(TreeNode root) {if (root != null) {traverse(root, String.valueOf(root.val));}return paths;}private void traverse(TreeNode root, String path) {if (root.left == null && root.right == null) {paths.add(path);}if (root.left != null) {traverse(root.left, path + "->" + root.left.val);}if (root.right != null) {traverse(root.right, path + "->" + root.right.val);}}
}

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解题思路

实现代码

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