本文实例为大家分享了C语言实现三子棋的具体代码，供大家参考，具体内容如下

效果如下：

代码实现：

头文件部分

#pragma once

#include

#include

#include

#define ROW 3

#define COL 3

//函数声明

void Initboard(char board[ROW][COL], int row, int col);

void Displayboard(char board[ROW][COL], int row, int col);

Player(char board[ROW][COL], int row, int col);

Computer(char board[ROW][COL], int row, int col);

char Judge(char board[ROW][COL], int row, int col);

函数部分

#include "game.h"

void Initboard(char board[ROW][COL], int row, int col)

{

int i = 0;

int j = 0;

for (i = 0; i < row; i++)

for (j = 0; j < col; j++)

board[i][j] = ' ';

}

//棋盘

// x | x | x

//---|---|---

// x | x | x

//---|---|---

// x | x | x

void Displayboard(char board[ROW][COL], int row, int col)

{

int i = 0;

int j = 0;

for (i = 0; i < row; i++)

{

//打印一行数据

for (j = 0; j < col; j++)

{

printf(" %c ", board[i][j]);

if (j < col - 1)

printf("|");

}

printf("\n");

//打印分隔行

if(i

for (j = 0; j < col; j++)

{

printf("---");

if (j < col - 1)

printf("|");

}

printf("\n");

}

}

Player(char board[ROW][COL], int row, int col)

{

while (1)

{

int x = 0;

int y = 0;

printf("请输入你的棋子坐标(如第一行第一列为1 1)：\n");

scanf("%d%d", &x, &y);

if (x <= row && x >= 1 && y <= col && y >= 1)

{

if (board[x - 1][y - 1] == ' ')

{

board[x - 1][y - 1] = '*';

break;

}

else

{

printf("该处已有棋子，请重新输入\n");

continue;

}

}

else

printf("坐标范围错误,请重新输入");

}

}

Computer(char board[ROW][COL], int row, int col)

{

int x = 0;

int y = 0;

while (1)

{

x = rand() % ROW;

y = rand() % COL;

if (board[x][y] == ' ')

{

board[x][y] = '#';

break;

}

}

}

int IsFull(char board[ROW][COL], int row, int col)//返回1表示棋盘已满，0表示棋盘没满

{

int i, j;

for (i = 0; i < row; i++)

{

for (j = 0; j < col; j++)

if (board[i][j] == ' ')

return 0;

}

return 1;

}

char Judge(char board[ROW][COL], int row,int col)

{

int i = 0;

//行有三个相连的情况

for (i = 0; i < row; i++)

{

if (board[i][0] == board[i][1] && board[i][1]==

board[i][2] && board[i][0] != ' ')

return board[i][0];

}

//列有三个相连的情况

for (i = 0; i < col; i++)

{

if (board[0][i] == board[1][i] && board[1][i]==

board[2][i] && board[0][i] != ' ')

return board[0][i];

}

//对角线三个相连的情况

if (board[0][0] == board[1][1]&& board[1][1]==board[2][2]&&board[0][0]!=' '

|| board[0][2] == board[1][1]&&board[1][1] == board[2][0]&&board[0][2] != ' ')

return board[1][1];

//平局的情况(棋盘满了)

if (IsFull( board , ROW,COL) ==1)

{

return 'E';

}

return 'C';

}

主函数部分

#include "game.h"

void menu()

{

printf("***************************\n");

printf("***1.开始游戏 0.退出游戏***\n");

printf("***************************\n");

printf("请输入数字1或0:");

}

void game()

{

char r;

char board[ROW][COL] = { 0 };

//初始化棋盘(清空棋盘)

Initboard(board, ROW, COL);

//打印棋盘

Displayboard(board, ROW, COL);

//人机对弈

while (1)

{

Player(board, ROW, COL);

Displayboard(board, ROW, COL);

r = Judge(board, ROW, COL);

if (r != 'C')

break;

Computer(board, ROW, COL);

Displayboard(board, ROW, COL);

r = Judge(board, ROW, COL);

if (r != 'C')

break;

}

//判断输赢

if (r == '*')

{

printf("玩家赢\n");

}

else if (r == '#')

{

printf("电脑赢\n");

}

else if (r == 'E')

{

printf("平局\n");

}

}

int main()

{

srand((unsigned int)time(NULL));

int input = 0;

do

{

menu();

scanf("%d", &input);

switch (input)

{

case 1:

printf("开始游戏\n");

game();

break;

case 0:

printf("退出游戏\n");

break;

default:

printf("请输入正确的选项\n");

break;

}

} while (input);

printf("游戏结束！");

return 0;

}

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持脚本之家。