class path resource [springMVC-servlet.xml] cannot be opened because it does not exist

SpringMVC web项目启动报错：

严重: Context initialization failed
org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [springMVC-servlet.xml]; nested exception isjava.io.FileNotFoundException: class path resource [springMVC-servlet.xml] cannot be opened because it does not exist

这里写一下有关DispatcherServlet前端控制器配置文件的编写和存放位置
1、servlet标签下的init-param标签是为配置文件指定新的位置，如果配置文件xxx-servlet在默认配置文件下即在WEB-INF下就尽量不要配init-param了，配置反而会出错
2、如果是配置文件放在WEB-INF默认读取地址需要遵循xxx-servlet.xml的命名格式；且xxx要和servlet-name>springMVC</servlet-name 里的值一样
3、如果没把配置文件xml放在默认目录下（WEB-INF）,就配上init-param，告诉服务器去哪找配置文件；此时的配置文件名可以自己定义

web.xml中
<servlet><servlet-name>springMVC</servlet-name><servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class><!-- 为配置文件指定新的位置，如果配置文件xxx-servlet在默认配置文件下即WEB-INF下就尽量不要配了，配置反而会出错 --><!-- <init-param> <param-name>contextConfigLocation</param-name> <param-value>classpath:springMVC-servlet.xml</param-value> </init-param> --><load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping><servlet-name>springMVC</servlet-name><url-pattern>/</url-pattern>
</servlet-mapping>

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