下面是可以在SQL Server中使用的通用脚本。只需修改开始日期和结束日期：

IF EXISTS (SELECT * FROM information_schema.tables WHERE Table_Name = 'Calendar' AND Table_Type = 'BASE TABLE')

BEGIN

DROP TABLE [Calendar]

END

CREATE TABLE [Calendar]

(

[CalendarDate] DATETIME

)

DECLARE @StartDate DATETIME

DECLARE @EndDate DATETIME

SET @StartDate = GETDATE()

SET @EndDate = DATEADD(d, 365, @StartDate)

WHILE @StartDate <= @EndDate

BEGIN

INSERT INTO [Calendar]

(

CalendarDate

)

SELECT

@StartDate

SET @StartDate = DATEADD(dd, 1, @StartDate)

END

如果您想要一个更高级的日历，这是我不久前在网上找到的一个日历：

CREATE SCHEMA Auxiliary

-- We put our auxiliary tables and stuff in a separate schema

-- One of the great new things in SQL Server 2005

go

CREATE FUNCTION Auxiliary.Computus

-- Computus (Latin for computation) is the calculation of the date of

-- Easter in the Christian calendar

-- http://en.wikipedia.org/wiki/Computus

-- I'm using the Meeus/Jones/Butcher Gregorian algorithm

(

@Y INT -- The year we are calculating easter sunday for

)

RETURNS DATETIME

AS

BEGIN

DECLARE

@a INT,

@b INT,

@c INT,

@d INT,

@e INT,

@f INT,

@g INT,

@h INT,

@i INT,

@k INT,

@L INT,

@m INT

SET @a = @Y % 19

SET @b = @Y / 100

SET @c = @Y % 100

SET @d = @b / 4

SET @e = @b % 4

SET @f = (@b + 8) / 25

SET @g = (@b - @f + 1) / 3

SET @h = (19 * @a + @b - @d - @g + 15) % 30

SET @i = @c / 4

SET @k = @c % 4

SET @L = (32 + 2 * @e + 2 * @i - @h - @k) % 7

SET @m = (@a + 11 * @h + 22 * @L) / 451

RETURN(DATEADD(month, ((@h + @L - 7 * @m + 114) / 31)-1, cast(cast(@Y AS VARCHAR) AS Datetime)) + ((@h + @L - 7 * @m + 114) % 31))

END

GO

CREATE TABLE [Auxiliary].[Calendar] (

-- This is the calendar table

[Date] datetime NOT NULL,

[Year] int NOT NULL,

[Quarter] int NOT NULL,

[Month] int NOT NULL,

[Week] int NOT NULL,

[Day] int NOT NULL,

[DayOfYear] int NOT NULL,

[Weekday] int NOT NULL,

[Fiscal_Year] int NOT NULL,

[Fiscal_Quarter] int NOT NULL,

[Fiscal_Month] int NOT NULL,

[KindOfDay] varchar(10) NOT NULL,

[Description] varchar(50) NULL,

PRIMARY KEY CLUSTERED ([Date])

)

GO

ALTER TABLE [Auxiliary].[Calendar]

-- In Celkoish style I'm manic about constraints (Never use em ;-))

-- http://www.celko.com/

ADD CONSTRAINT [Calendar_ck] CHECK (  ([Year] > 1900)

AND ([Quarter] BETWEEN 1 AND 4)

AND ([Month] BETWEEN 1 AND 12)

AND ([Week]  BETWEEN 1 AND 53)

AND ([Day] BETWEEN 1 AND 31)

AND ([DayOfYear] BETWEEN 1 AND 366)

AND ([Weekday] BETWEEN 1 AND 7)

AND ([Fiscal_Year] > 1900)

AND ([Fiscal_Quarter] BETWEEN 1 AND 4)

AND ([Fiscal_Month] BETWEEN 1 AND 12)

AND ([KindOfDay] IN ('HOLIDAY', 'SATURDAY', 'SUNDAY', 'BANKDAY')))

GO

SET DATEFIRST 1;

-- I want my table to contain datedata acording to ISO 8601

-- http://en.wikipedia.org/wiki/ISO_8601

-- thus first day of a week is monday

WITH Dates(Date)

-- A recursive CTE that produce all dates between 1999 and 2020-12-31

AS

(

SELECT cast('1999' AS DateTime) Date -- SQL Server supports the ISO 8601 format so this is an unambigious shortcut for 1999-01-01

UNION ALL                            -- http://msdn2.microsoft.com/en-us/library/ms190977.aspx

SELECT (Date + 1) AS Date

FROM Dates

WHERE

Date < cast('2021' AS DateTime) -1

),

DatesAndThursdayInWeek(Date, Thursday)

-- The weeks can be found by counting the thursdays in a year so we find

-- the thursday in the week for a particular date

AS

(

SELECT

Date,

CASE DATEPART(weekday,Date)

WHEN 1 THEN Date + 3

WHEN 2 THEN Date + 2

WHEN 3 THEN Date + 1

WHEN 4 THEN Date

WHEN 5 THEN Date - 1

WHEN 6 THEN Date - 2

WHEN 7 THEN Date - 3

END AS Thursday

FROM Dates

),

Weeks(Week, Thursday)

-- Now we produce the weeknumers for the thursdays

-- ROW_NUMBER is new to SQL Server 2005

AS

(

SELECT ROW_NUMBER() OVER(partition by year(Date) order by Date) Week, Thursday

FROM DatesAndThursdayInWeek

WHERE DATEPART(weekday,Date) = 4

)

INSERT INTO Auxiliary.Calendar

SELECT

d.Date,

YEAR(d.Date) AS Year,

DATEPART(Quarter, d.Date) AS Quarter,

MONTH(d.Date) AS Month,

w.Week,

DAY(d.Date) AS Day,

DATEPART(DayOfYear, d.Date) AS DayOfYear,

DATEPART(Weekday, d.Date) AS Weekday,

-- Fiscal year may be different to the actual year in Norway the are the same

-- http://en.wikipedia.org/wiki/Fiscal_year

YEAR(d.Date) AS Fiscal_Year,

DATEPART(Quarter, d.Date) AS Fiscal_Quarter,

MONTH(d.Date) AS Fiscal_Month,

CASE

-- Holidays in Norway

-- For other countries and states: Wikipedia - List of holidays by country

-- http://en.wikipedia.org/wiki/List_of_holidays_by_country

WHEN (DATEPART(DayOfYear, d.Date) = 1)          -- New Year's Day

OR (d.Date = Auxiliary.Computus(YEAR(Date))-7)  -- Palm Sunday

OR (d.Date = Auxiliary.Computus(YEAR(Date))-3)  -- Maundy Thursday

OR (d.Date = Auxiliary.Computus(YEAR(Date))-2)  -- Good Friday

OR (d.Date = Auxiliary.Computus(YEAR(Date)))    -- Easter Sunday

OR (d.Date = Auxiliary.Computus(YEAR(Date))+39) -- Ascension Day

OR (d.Date = Auxiliary.Computus(YEAR(Date))+49) -- Pentecost

OR (d.Date = Auxiliary.Computus(YEAR(Date))+50) -- Whitmonday

OR (MONTH(d.Date) = 5 AND DAY(d.Date) = 1)      -- Labour day

OR (MONTH(d.Date) = 5 AND DAY(d.Date) = 17)     -- Constitution day

OR (MONTH(d.Date) = 12 AND DAY(d.Date) = 25)    -- Cristmas day

OR (MONTH(d.Date) = 12 AND DAY(d.Date) = 26)    -- Boxing day

THEN 'HOLIDAY'

WHEN DATEPART(Weekday, d.Date) = 6 THEN 'SATURDAY'

WHEN DATEPART(Weekday, d.Date) = 7 THEN 'SUNDAY'

ELSE 'BANKDAY'

END KindOfDay,

CASE

-- Description of holidays in Norway

WHEN (DATEPART(DayOfYear, d.Date) = 1)            THEN 'New Year''s Day'

WHEN (d.Date = Auxiliary.Computus(YEAR(Date))-7)  THEN 'Palm Sunday'

WHEN (d.Date = Auxiliary.Computus(YEAR(Date))-3)  THEN 'Maundy Thursday'

WHEN (d.Date = Auxiliary.Computus(YEAR(Date))-2)  THEN 'Good Friday'

WHEN (d.Date = Auxiliary.Computus(YEAR(Date)))    THEN 'Easter Sunday'

WHEN (d.Date = Auxiliary.Computus(YEAR(Date))+39) THEN 'Ascension Day'

WHEN (d.Date = Auxiliary.Computus(YEAR(Date))+49) THEN 'Pentecost'

WHEN (d.Date = Auxiliary.Computus(YEAR(Date))+50) THEN 'Whitmonday'

WHEN (MONTH(d.Date) = 5 AND DAY(d.Date) = 1)      THEN 'Labour day'

WHEN (MONTH(d.Date) = 5 AND DAY(d.Date) = 17)     THEN 'Constitution day'

WHEN (MONTH(d.Date) = 12 AND DAY(d.Date) = 25)    THEN 'Cristmas day'

WHEN (MONTH(d.Date) = 12 AND DAY(d.Date) = 26)    THEN 'Boxing day'

END Description

FROM DatesAndThursdayInWeek d

-- This join is for getting the week into the result set

inner join Weeks w

on d.Thursday = w.Thursday

OPTION(MAXRECURSION 0)

GO

CREATE FUNCTION Auxiliary.Numbers

(

@AFrom INT,

@ATo INT,

@AIncrement INT

)

RETURNS @RetNumbers TABLE

(

[Number] int PRIMARY KEY NOT NULL

)

AS

BEGIN

WITH Numbers(n)

AS

(

SELECT @AFrom AS n

UNION ALL

SELECT (n + @AIncrement) AS n

FROM Numbers

WHERE

n < @ATo

)

INSERT @RetNumbers

SELECT n from Numbers

OPTION(MAXRECURSION 0)

RETURN;

END

GO

CREATE FUNCTION Auxiliary.iNumbers

(

@AFrom INT,

@ATo INT,

@AIncrement INT

)

RETURNS TABLE

AS

RETURN(

WITH Numbers(n)

AS

(

SELECT @AFrom AS n

UNION ALL

SELECT (n + @AIncrement) AS n

FROM Numbers

WHERE

n < @ATo

)

SELECT n AS Number from Numbers

)

GO