n = int(input('请输入年份:'))
if n % 400 == 0 or n % 4 == 0 and n % 100 != 0:print('{0}是闰年'.format(n))
else:print('{0}不是闰年'.format(n))

import calendarn = int(input("请输入年份："))
year = calendar.isleap(n)
if year == True:print ("{0}是闰年".format(n))
else:print ("{0}不是闰年".format(n))

n = int(input(''))
if n > 1:for i in range(2,n):if n % i == 0:print('{0}不是质数'.format(n))print('{n}={a}*{b}'.format(n=n,a=i,b=int(n/i)))    # 这里也可为b=n//ibreakelse:print('{0}是质数'.format(n))break

n = int(input(''))
if n > 1:m1 = 0;m2 = 0for i in range(2,n):if n % i == 0:str = '{0}不是质数'.format(n)print('{n}={a}*{b}'.format(n=n,a=i,b=int(n/i)))    # 这里也可为b=n//im1 = 1;m2 = 1elif m1==0:print('{0}是质数'.format(n))breakif [m1,m2].count(1) == 2:print('{0}不是质数'.format(n))

num = int(input(""))
i = 2
while i < num:s = num % iif s == 0:breakelse:i += 1
if num == i:print("{0}是质数".format(num))
else:print("{0}不是质数".format(num))

my_index1,my_index2 = map(int,input('请选择一个范围:').split(','))
result = []for num in range(my_index1,my_index2+1):if num > 1:for i in range(2,num):if (num % i) == 0:breakelse:result.append(num)
print('{a}到{b}所有的质数有:{c}'.format(a = my_index1,b = my_index2,c = result))

def yueSeFu(m,n,k):serial_num = list(range(1,m +1))    # 创建从1到m的序号index = 0                            # 设置外部变量indexwhile len(serial_num) > m - n:        # 当最后剩余人数为m - n之前，一直进行下面的程序for i in serial_num:            # 遍历每个编号index += 1                     # 把外部变量index进行真实遍历if index == k:                # 当外部变量index找到k时，进行下面代码块的操作serial_num.remove(i)    # 移除需要下船的人的编号index = 1                # 这时候index已经找到序号k了，就要重新遍历print('{0}号人下船了'.format(i))if __name__ == '__main__':# 传入起始人数m，需要下船的人数n，数到多少下船的序号k,这里可自行设置yueSeFu(30,15,9)

def yueSeFu(m,n,k):people = list(range(1, m+1))i = 0while len(people) > m - n:i += (k - 1)if i >= len(people):i -= len(people)print("{}号下船了".format(people[i]))del people[i]if __name__ == '__main__':# 传入起始人数m，需要下船的人数n，数到多少下船的序号kyueSeFu(30,15,9)

def twoSearch(x,arr,begin,end):    # x为要查询的元素,arr为数组,begin和and是每次查找的范围if end >= 1:mid = int(begin + (end-1)/2)    # 每次范围的元素中间位置if int(arr[mid]) == x:return midelif int(arr[mid]) > x:        # 元素小于中间的元素，需要比较左边的元素return twoSearch(x,arr,begin,end - 1)else:                    # 元素大于中间的元素，需要比较右边的元素return twoSearch(x,arr,begin + 1,end)else:return -1if __name__ == '__main__':my_arr = list(map(int,input('请输入数组:').split(',')))    # 返回可迭代对象my_x = int(input('请输入要查找的元素:'))result = twoSearch(my_x, my_arr, 0, len(my_arr) - 1)if result != -1:print('元素在数组中的索引为:{0}'.format(result))else:print('元素不在数组中')

def twoSum(nums, target):for index1,i in enumerate(nums):for index2,j in enumerate(nums):if i+j == target and i != j:return index1,index2a = list(map(int,input().split(',')))
b = int(input())
print(list(twoSum(a,b)))

for index1,i in enumerate(nums):for index2,j in enumerate(nums):if i+j == target and i != j:return index1,index2

for i in range(len(nums)):    # 循环遍历列表# 这里是用和减去列表中的某一元素，并且两个元素下标不同，就返回两个下标if(target-nums[i] in nums and i != nums.index(target-nums[i])):return [i,nums.index(target-nums[i])]

my_dict = {}                        # 创建一个字典for index, num1 in enumerate(nums):    # 利用函数enumerate输出列表或数组的下标和元素num2 = target - num1            # 另一个元素# 这里是判断，如果字典中有另一个元素值的话，返回下标，以及该元素下标# 这里由于字典是键值对，就避免了两个元素和符合，单元素是同一个元素的情况if num2 in my_dict:                return [my_dict[num2], index]# 把字典中的元素对应于键my_dict[num1] = indexreturn -1

my_set = set(nums)for i, v in enumerate(nums):if (target - v) in my_set and i != nums.index(target - v):return [i, nums.index(target - v)]