leetCode 110. Balanced Binary Tree 平衡二叉树

110. Balanced Binary Tree

Given a binary tree, determine if it is height-balanced.

For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.

题目大意：

判断一颗二叉树是否为平衡二叉树。

思路：

做一个辅助函数来求的树的高度。
通过辅助函数来递归求解。

代码如下：

/*** Definition for a binary tree node.* struct TreeNode {*     int val;*     TreeNode *left;*     TreeNode *right;*     TreeNode(int x) : val(x), left(NULL), right(NULL) {}* };*/
class Solution {
public:int depth(TreeNode* root){if(!root)return 0;int l = depth(root->left) ;int r = depth(root->right) ;return 1 + ((l > r)?l:r);}bool isBalanced(TreeNode* root) {if(!root)return true;else{int l = depth(root->left);int r = depth(root->right);if(l + 1 < r || r + 1 <l){return false;}elsereturn (isBalanced(root->left) && isBalanced(root->right) );}}
};

2016-08-08 00:25:26

转载于:https://blog.51cto.com/qiaopeng688/1835477

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