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public static String sendGetRequest(String path, Map params, String enc) throws IOException {

/*

* http://127.0.0.1/AndroidService/android/upload?title=aaa&timelength=90的形式

*/

StringBuilder sb = new StringBuilder(path);

sb.append('?');

for(Map.Entry entry : params.entrySet()) {

sb.append(entry.getKey()).append('=').append(URLEncoder.encode(entry.getValue(), enc)).append('&');

}

sb.deleteCharAt(sb.length()-1);

try {

URL url = new URL(sb.toString());

HttpURLConnection conn = (HttpURLConnection)url.openConnection();

conn.setRequestMethod("GET"); //设置方法为GET

conn.setReadTimeout(5 * 1000); //设置过期时间为5秒

if(conn.getResponseCode() == 200) { //如果成功返回

InputStream inStream = conn.getInputStream();//通过输入流获取html数据

String s2 = changeInputStream(inStream,"UTF-8");

return s2;

}

} catch (MalformedURLException e) {

e.printStackTrace();

Log.e(TAG, e.toString());

return "";

}

return "";

}

/**

* 将一个输入流转换成指定编码的字符串

*

* @param inputStream

* @param encode

* @return

*/

private static String changeInputStream(InputStream inputStream,

String encode) {

// 内存流

ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();

byte[] data = new byte[1024];

int len = 0;

String result = null;

if (inputStream != null) {

try {

while ((len = inputStream.read(data)) != -1) {

byteArrayOutputStream.write(data, 0, len);

}

result = new String(byteArrayOutputStream.toByteArray(), encode);

} catch (IOException e) {

e.printStackTrace();

}

}

return result;

}

我当前的changeInputStream方法返回值是返回一个字符串，我如果是返回一个对象，我这个changeInputStream方法该怎么写呢？求大神教教俺啊！