我看到的第一个问题是你在前锋线上留下了一个“r”。t.forwad(length)

应该是t.forward(length)

另外，如果使用input()width和length将是字符串，但它们需要进行类型转换。Specifically，长度必须是整数或浮点数，宽度必须是正整数。length = None

while not length:

try:

length = float(input('Enter your preferred turtle line length: '))

except ValueError:

print('You need to enter a number')

width = None

while not width:

try:

width = int(input('Enter your preferred turtle line width: '))

except ValueError:

print('You need to enter a positive integer')

else:

if width < 1:

print('You need to enter a positive integer')

width = None

我这里的代码将使用循环从用户那里获得正确的输入。它将尝试拒绝错误的输入。例如，如果用户在询问长度时键入“pumpkin”。

类似地，我捕获长度和宽度条目问题的方式，您将希望捕获形状和颜色的用户条目问题。确保用户输入有效的颜色。确保形状在允许的形状列表中。

最后一个问题是这里的代码缩进不正确。您需要在if:和else:子句之后缩进。

下面是整个程序的工作原理：import turtle

s = turtle.Screen()

t = turtle.Turtle()

length = None

while not length:

try:

length = float(input('Enter your preferred turtle line length: '))

except ValueError:

print('You need to enter a number')

width = None

while not width:

try:

width = int(input('Enter your preferred turtle line width: '))

except ValueError:

print('You need to enter a positive integer')

else:

if width < 1:

print('You need to enter a positive integer')

width = None

color = None

while not color:

color = input('Enter your preferred turtle line color: ')

try:

t.pencolor(color)

except:

print('You need to enter a color that I know.')

color = None

shape = None

while not shape:

shape = input('Specify whether you want to draw a line, triangle, or square: ')

if shape.lower() not in ['line', 'triangle', 'square']:

shape = None

print('I only draw lines, triangles and squares!')

t.pensize(width)

if shape.lower() == 'line':

t.forward(length)

elif shape.lower() == 'triangle':

t.forward(length)

t.right(120)

t.forward(length)

t.right(120)

t.forward(length)

else:

t.forward(length)

t.right(90)

t.forward(length)

t.right(90)

t.forward(length)

t.right(90)

t.forward(length)

s.exitonclick()

注意，我也修正了三角形。。。