LeetCode——Find the Difference

Question

Given two strings s and t which consist of only lowercase letters.

String t is generated by random shuffling string s and then add one more letter at a random position.

Find the letter that was added in t.

Example:

Input:
s = "abcd"
t = "abcde"

Output:
e

Explanation:
'e' is the letter that was added.

Solution

用hash table求解，时间复杂度为O(2n)
用异或求解，这道题和single number 的问题是一个意思，两个字符串中，找出那个单个的字符。时间复杂度为O(n)。

Answer

class Solution {
public:char findTheDifference(string s, string t) {map<char, int> dict;for (char c : s)dict[c]++;map<char, int> dict2;for (char c : t) {dict2[c]++;if (dict2[c] > dict[c])return c;}}
};

用异或求解。

class Solution {
public:char findTheDifference(string s, string t) {char r=0;for(char c:s) r ^=c;for(char c:t) r ^=c;return r;}
};

转载于:https://www.cnblogs.com/zhonghuasong/p/6658700.html

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LeetCode——Find the Difference

LeetCode——Find the Difference

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