Visual Studio 单元测试的简单应用

写在前面

  笔者根据作业的介绍以及Visual Studio 2017 文档的相关说明，进行了Visual Studio 单元测试的简单应用。

单元测试代码

  单元测试从以下三方面展开：

1. 四则运算正确性；
2. 四则运算组合后计算的正确性；
3. 要求范围内所有整数运算的正确性；

#include "stdafx.h"
#include "CppUnitTest.h"
#include "../Calculator/Calculator.h"using namespace Microsoft::VisualStudio::CppUnitTestFramework;namespace CalculatorUnitTest
{       TEST_CLASS(Test){public:Calculator* calc;TEST_METHOD_INITIALIZE(initCal) {calc = new Calculator();}TEST_METHOD_CLEANUP(CleanCal){delete calc;calc = NULL;}/*简单测试*/TEST_METHOD(SimpleADD){string ret = calc->Solve("11+22");Assert::AreEqual(ret, (string)"11+22=33");}TEST_METHOD(SimpleSUB){string ret = calc->Solve("77-33");Assert::AreEqual(ret, (string)"77-33=44");}TEST_METHOD(SimpleMUL){string ret = calc->Solve("55*66");Assert::AreEqual(ret, (string)"55*66=3630");}TEST_METHOD(SimpleDIV){string ret = calc->Solve("99/33");Assert::AreEqual(ret, (string)"99/33=3");}/*组合测试*/TEST_METHOD(ADD_ADD){string ret = calc->Solve("22+33+11");Assert::AreEqual(ret, (string)"22+33+11=66");}TEST_METHOD(ADD_SUB){string ret = calc->Solve("22+33-11");Assert::AreEqual(ret, (string)"22+33-11=44");}TEST_METHOD(ADD_MUL){string ret = calc->Solve("22+33*11");Assert::AreEqual(ret, (string)"22+33*11=385");}TEST_METHOD(ADD_DIV){string ret = calc->Solve("22+33/11");Assert::AreEqual(ret, (string)"22+33/11=25");}TEST_METHOD(SUB_ADD){string ret = calc->Solve("99-66+77");Assert::AreEqual(ret, (string)"99-66+77=110");}TEST_METHOD(SUB_SUB){string ret = calc->Solve("99-22-55");Assert::AreEqual(ret, (string)"99-22-55=22");}TEST_METHOD(SUB_MUL){string ret = calc->Solve("77-6*11");Assert::AreEqual(ret, (string)"77-6*11=11");}TEST_METHOD(SUB_DIV){string ret = calc->Solve("77-88/2");Assert::AreEqual(ret, (string)"77-88/2=33");}TEST_METHOD(MUL_ADD){string ret = calc->Solve("22*33+11");Assert::AreEqual(ret, (string)"22*33+11=737");}TEST_METHOD(MUL_SUB){string ret = calc->Solve("22*33-11");Assert::AreEqual(ret, (string)"22*33-11=715");}TEST_METHOD(MUL_MUL){string ret = calc->Solve("22*33*99");Assert::AreEqual(ret, (string)"22*33*99=71874");}TEST_METHOD(MUL_DIV){string ret = calc->Solve("22*33/11");Assert::AreEqual(ret, (string)"22*33/11=66");}TEST_METHOD(DIV_ADD){string ret = calc->Solve("99/9+11");Assert::AreEqual(ret, (string)"99/9+11=22");}TEST_METHOD(DIV_SUB){string ret = calc->Solve("99/9-10");Assert::AreEqual(ret, (string)"99/9-10=1");}TEST_METHOD(DIV_MUL){string ret = calc->Solve("99/9*22");Assert::AreEqual(ret, (string)"99/9*22=242");}TEST_METHOD(DIV_DIV){string ret = calc->Solve("99/9/11");Assert::AreEqual(ret, (string)"99/9/11=1");}/*运算数长度*/TEST_METHOD(Length_1){string ret = calc->Solve("9/3*2+8");Assert::AreEqual(ret, (string)"9/3*2+8=14");}TEST_METHOD(Length_2){string ret = calc->Solve("90/3*22+8");Assert::AreEqual(ret, (string)"90/3*22+8=668");}TEST_METHOD(Length_3){string ret = calc->Solve("90/30*2+89");Assert::AreEqual(ret, (string)"90/30*2+89=95");}};}

Bug修复

  经过调试，对源程序的以下三个部分进行修复。

string Calculator::Solve(string formula) {vector<string>* tempStack = new vector<string>();stack<char>* operatorStack = new stack<char>();int len = formula.length();int k = 0;for (int j = -1; j < len - 1; j++) {char formulaChar = formula[j + 1];if (j == len - 2 || formulaChar == '+' || formulaChar == '-' ||formulaChar == '*' || formulaChar == '/') {if (j == len - 2) {tempStack->push_back(formula.substr(k));}else {if (k <= j) {   // 判断条件错误：k < j ===> k <= j/*substr 使用错误:tempStack->push_back(formula.substr(k, j + 1));*//*----------修改后----------*/tempStack->push_back(formula.substr(k, j - k + 1)); /*--------------------------*/}if (operatorStack->empty()) {operatorStack->push(formulaChar);}else {char stackChar = operatorStack->top();if ((stackChar == '+' || stackChar == '-')&& (formulaChar == '*' || formulaChar == '/')) {operatorStack->push(formulaChar);}else {/*to_string 使用错误:tempStack->push_back(to_string(operatorStack->top()));  *//*----------修改后----------*/string tempOp(1, operatorStack->top());tempStack->push_back(tempOp);/*--------------------------*/operatorStack->pop();operatorStack->push(formulaChar);}}}k = j + 2;}}
// 以下略。

• 错误一导致一位数计算时无法将字符串中的数字截取插入临时栈(tempStack)。
• 错误二导致截取数字时截取到错误的长度的子串。
• 错误三会将运算符转换为相应的ASCII码，导致插入临时栈的为数字字符串而非运算符字符串。