-- private JavaMailSender sender; 可能会出现注入错误，请注意yam配置文件中格式是否一致；否则会找不到注入的bean

一 发送邮件

在Springboot中发送邮件非常简单。

pom.xml引入maven依赖

org.springframework.boot

spring-boot-starter-mail

在application.yml里设置发信人的账号、密码

spring:

mail:

host: smtp.qq.com

username: 27255XXXX@qq.com

password: njcvcbdkrofgbhie

properties:

mail:

smtp:

auth: true

starttls:

enable: true

required: true

这个username就是未来发信时的邮箱地址，password是授权码。

这里以普通qq邮箱为例，注意password不是qq密码，而是授权码。

在qq邮箱-设置-账户，找到图片中的地方，开启IMAP/SMTP服务，开启后才能在别的客户端使用该qq邮箱发邮件，然后生成授权码，填写到application.yml的password位置。

然后就可以使用该邮箱作为发件人了。

packagecom.zhx.commonservice.common.service;importorg.slf4j.Logger;importorg.slf4j.LoggerFactory;importorg.springframework.beans.factory.annotation.Autowired;importorg.springframework.beans.factory.annotation.Value;importorg.springframework.core.io.FileSystemResource;importorg.springframework.mail.SimpleMailMessage;importorg.springframework.mail.javamail.JavaMailSender;importorg.springframework.mail.javamail.MimeMessageHelper;importorg.springframework.stereotype.Service;importjavax.mail.MessagingException;importjavax.mail.internet.MimeMessage;importjava.io.File;/*** @Author: SimonHu

* @Date: 2019/5/23 9:04

* @Description:*/@Servicepublic classMailService {private final Logger logger = LoggerFactory.getLogger(this.getClass());

@AutowiredprivateJavaMailSender sender;

@Value("${spring.mail.username}")privateString from;/*** 发送纯文本的简单邮件

*@paramto

*@paramsubject

*@paramcontent*/

public voidsendSimpleMail(String to, String subject, String content){

SimpleMailMessage message= newSimpleMailMessage();

String[] toRecive= to.split(",");

message.setFrom(from);

message.setTo(toRecive);

message.setSubject(subject);

message.setText(content);try{

sender.send(message);

logger.info("简单邮件已经发送。");

}catch(Exception e) {

logger.error("发送简单邮件时发生异常！", e);

}

}/*** 发送html格式的邮件

*@paramto

*@paramsubject

*@paramcontent*/

public voidsendHtmlMail(String to, String subject, String content){

MimeMessage message=sender.createMimeMessage();try{

String[] toRecive= to.split(",");//true表示需要创建一个multipart message

MimeMessageHelper helper = new MimeMessageHelper(message, true);

helper.setFrom(from);

helper.setTo(toRecive);

helper.setSubject(subject);

helper.setText(content,true);

sender.send(message);

logger.info("html邮件已经发送。");

}catch(MessagingException e) {

logger.error("发送html邮件时发生异常！", e);

}

}/*** 发送带附件的邮件

*@paramto

*@paramsubject

*@paramcontent

*@paramfilePath*/

public voidsendAttachmentsMail(String to, String subject, String content, String filePath){

MimeMessage message=sender.createMimeMessage();try{

String[] toRecive= to.split(",");//true表示需要创建一个multipart message

MimeMessageHelper helper = new MimeMessageHelper(message, true);

helper.setFrom(from);

helper.setTo(toRecive);

helper.setSubject(subject);

helper.setText(content,true);

FileSystemResource file= new FileSystemResource(newFile(filePath));

String fileName=filePath.substring(filePath.lastIndexOf(File.separator));

helper.addAttachment(fileName, file);

sender.send(message);

logger.info("带附件的邮件已经发送。");

}catch(MessagingException e) {

logger.error("发送带附件的邮件时发生异常！", e);

}

}/*** 发送嵌入静态资源(一般是图片)的邮件

*@paramto

*@paramsubject

*@paramcontent 邮件内容，需要包括一个静态资源的id，比如：

*@paramrscPath 静态资源路径和文件名

*@paramrscId 静态资源id*/

public voidsendInlineResourceMail(String to, String subject, String content, String rscPath, String rscId){

MimeMessage message=sender.createMimeMessage();try{

String[] toRecive= to.split(",");//true表示需要创建一个multipart message

MimeMessageHelper helper = new MimeMessageHelper(message, true);

helper.setFrom(from);

helper.setTo(toRecive);

helper.setSubject(subject);

helper.setText(content,true);

FileSystemResource res= new FileSystemResource(newFile(rscPath));

helper.addInline(rscId, res);

sender.send(message);

logger.info("嵌入静态资源的邮件已经发送。");

}catch(MessagingException e) {

logger.error("发送嵌入静态资源的邮件时发生异常！", e);

}

}

}

然后就可以使用里面的方法发邮件了。

可以先写个简单的测试类，调用

mailService.sendSimpleMail("wuweifeng@XXX.com", "主题：简单邮件", "测试邮件内容");

填写个收信人的地址就OK了。然后就能收到邮件了。收信人可以有多个，通过SimpleMailMessage可以看到。

二 拦截全局异常并发邮件

定义一个全局拦截类

package com.tianyalei.testmail.global;

import com.tianyalei.testmail.service.MailService;

import org.slf4j.Logger;

import org.slf4j.LoggerFactory;

import org.springframework.beans.factory.annotation.Autowired;

import org.springframework.http.HttpHeaders;

import org.springframework.http.HttpStatus;

import org.springframework.http.ResponseEntity;

import org.springframework.web.bind.annotation.ControllerAdvice;

import org.springframework.web.bind.annotation.ExceptionHandler;

import org.springframework.web.bind.annotation.ResponseBody;

import org.springframework.web.context.request.WebRequest;

import org.springframework.web.servlet.mvc.method.annotation.ResponseEntityExceptionHandler;

import javax.servlet.http.HttpServletRequest;

import java.io.PrintWriter;

import java.io.StringWriter;

import java.util.Enumeration;

import static org.springframework.http.HttpStatus.NOT_EXTENDED;

/**

* Created by wuwf on 17/3/31.

* 全局异常处理

*/

@ControllerAdvice

public class GlobalExceptionHandler extends ResponseEntityExceptionHandler {

private Logger logger = LoggerFactory.getLogger(getClass().getName());

@Autowired

private MailService mailService;

/**

* 在controller里面内容执行之前，校验一些参数不匹配啊，Get post方法不对啊之类的

*/

@Override

protected ResponseEntity handleExceptionInternal(Exception ex, Object body, HttpHeaders headers, HttpStatus status, WebRequest request) {

System.out.println("错误");

return new ResponseEntity<>("出错了", NOT_EXTENDED);

}

@ExceptionHandler(value = Exception.class)

@ResponseBody

public String jsonHandler(HttpServletRequest request, Exception e) throws Exception {

log(e, request);

StringWriter sw = new StringWriter();

PrintWriter pw = new PrintWriter(sw);

e.printStackTrace(pw);

//发送邮件

mailService.sendSimpleMail("wuweifeng@XXXX.com", "异常", sw.toString());

return "发生异常";

}

private void log(Exception ex, HttpServletRequest request) {

logger.error("************************异常开始*******************************");

logger.error("请求地址：" + request.getRequestURL());

Enumeration enumeration = request.getParameterNames();

logger.error("请求参数");

while (enumeration.hasMoreElements()) {

String name = enumeration.nextElement().toString();

logger.error(name + "---" + request.getParameter(name));

}

StackTraceElement[] error = ex.getStackTrace();

for (StackTraceElement stackTraceElement : error) {

logger.error(stackTraceElement.toString());

}

logger.error("************************异常结束*******************************");

}

}