一、说明
二、原因
三、解决
- 1、原代码
- 2、修改后

一、说明

报错原因：访问类型为 null 的值的数组下标
7.2中是没问题的，7.4中对语法规范性更为严谨

二、原因

原文：Trying to use values of type null, bool, int, float or resource as an array (such as $null["key"]) will now generate a notice.
翻译：尝试将 null，bool，int，float 或 resource 类型的值用作数组 ( 例如 $null[“key”] ) 会产生一个通知。
传送门：https://www.php.net/manual/en/migration74.incompatible.php，截图如下：

三、解决

1、原代码

$result = $userDao->getOne();
if($result['status'] == 1) {} else {}

2、修改后

$result = $userDao->getOne();
if(!empty($result['status']) && ($result['status'] == 1)) {} else {}

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php7.4报错：Trying to access array offset on value of type null

一、说明

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三、解决

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