POJ 2210 Metric Time G++

#include <iostream>
#include <cstdio>
using namespace std;
int hs[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int he[13]={0,0,31,59,90,120,151,181,212,243,273,304,334};
int tian(int dy,int mh,int yr)//与 1.1.2000 相差几天
{int sum=dy-1;/*for(int i=1;i<mh;i++){if(i==2 && ((yr%4==0 && yr%100!=0)||(yr%400==0)))//闰年 {sum=sum+29;}else{sum=sum+hs[i];}}*/sum=sum+he[mh];if(mh>2 && ((yr%4==0 && yr%100!=0)||(yr%400==0)))//闰年{sum=sum+1;}/*for(int i=2000;i<yr;i++){if((i%4==0 && i%100!=0)||(i%400==0))//闰年 {sum=sum+366;}else{sum=sum+365;}       }*/if (yr !=2000)//抄博友 巧妙 sum =sum+ 366 + 365 * (yr - 1 - 2000) + (yr - 1 - 2000) /4- (yr -1 - 2000) / 100+ (yr -1-2000) / 400;    return sum;
}
int miao(int hr,int mn,int sc)
{return sc+mn*60+hr*60*60;
}
int main()
{/* for(int i=2;i<13;i++){he[i]=he[i-1]+hs[i-1];cout<<he[i]<<" ";}cout<<endl;*/int n;scanf("%d",&n);for(int i=0;i<n;i++){int hr,mn,sc,dy,mh,yr;scanf("%d:%d:%d %d.%d.%d",&hr,&mn,&sc,&dy,&mh,&yr);int msec=miao(hr,mn,sc);int mday=tian(dy,mh,yr);//cout<<msec<<" "<<mday<<endl;msec=msec*(125.0/(108.0));//cout<<msec<<endl;printf("%d:%d:%d %d.%d.%d\n",(msec/10000)%10,(msec%10000)/100,msec%100,(mday%100)+1,((mday%1000)/100)+1,mday/1000);}return 0;
}

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