1124. Raffle for Weibo Followers

John got a full mark on PAT. He was so happy that he decided to hold a raffle（抽奖） for his followers on Weibo -- that is, he would select winners from every N followers who forwarded his post, and give away gifts. Now you are supposed to help him generate the list of winners.

Input Specification:

Each input file contains one test case. For each case, the first line gives three positive integers M (<= 1000), N and S, being the total number of forwards, the skip number of winners, and the index of the first winner (the indices start from 1). Then M lines follow, each gives the nickname (a nonempty string of no more than 20 characters, with no white space or return) of a follower who has forwarded John's post.

Note: it is possible that someone would forward more than once, but no one can win more than once. Hence if the current candidate of a winner has won before, we must skip him/her and consider the next one.

Output Specification:

For each case, print the list of winners in the same order as in the input, each nickname occupies a line. If there is no winner yet, print "Keep going..." instead.

Sample Input 1:

9 3 2
Imgonnawin!
PickMe
PickMeMeMeee
LookHere
Imgonnawin!
TryAgainAgain
TryAgainAgain
Imgonnawin!
TryAgainAgain

Sample Output 1:

PickMe
Imgonnawin!
TryAgainAgain

Sample Input 2:

2 3 5
Imgonnawin!
PickMe

Sample Output 2:

Keep going...

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<map>
#include<string>
using namespace std;
int main()
{int m,n,s,f=0,num=0;map<string,int> winner;cin>>m>>n>>s;string a;for(int i=0;i<m;i++){cin>>a;//cout<<a<<endl;if(f==0){num++;//cout<<num<<endl;if(num==s){cout<<a<<endl;num=0;f=1;winner[a]=1;}}else{if(winner.find(a)==winner.end()){num++;if(num==n){cout<<a<<endl;num=0;winner[a]=1;}}}}if(f==0)cout<<"Keep going..."<<endl;return 0;
}

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