PAT 甲级 1011 World Cup Betting

With the 2010 FIFA World Cup running, football fans the world over were becoming increasingly excited as the best players from the best teams doing battles for the World Cup trophy in South Africa. Similarly, football betting fans were putting their money where their mouths were, by laying all manner of World Cup bets.

Chinese Football Lottery provided a “Triple Winning” game. The rule of winning was simple: first select any three of the games. Then for each selected game, bet on one of the three possible results – namely W for win, T for tie, and L for lose. There was an odd assigned to each result. The winner’s odd would be the product of the three odds times 65%.

For example, 3 games’ odds are given as the following:

 W    T    L
1.1  2.5  1.7
1.2  3.1  1.6
4.1  1.2  1.1

To obtain the maximum profit, one must buy W for the 3rd game, T for the 2nd game, and T for the 1st game. If each bet takes 2 yuans, then the maximum profit would be (4.1×3.1×2.5×65%−1)×2=39.31 yuans (accurate up to 2 decimal places).

Input Specification:

Each input file contains one test case. Each case contains the betting information of 3 games. Each game occupies a line with three distinct odds corresponding to W, T and L.

Output Specification:

For each test case, print in one line the best bet of each game, and the maximum profit accurate up to 2 decimal places. The characters and the number must be separated by one space.

Sample Input:

1.1 2.5 1.7
1.2 3.1 1.6
4.1 1.2 1.1
结尾无空行

Sample Output:

T T W 39.31
结尾无空行

题意描述：

找出每行中赔率最大的，输出它所对应的的字母，然后用题目所给的公式计算收益就可以了。

解题思路：

每一行的赔率是独立的，因此可以单独对每一行计算最值，把相应的字母以及赔率都存储起来，最后再根据公式计算即可。

难度评测：Easy

AC代码实现：

#include <bits/stdc++.h>
using namespace std;
typedef pair<double, char> P;int main() {char ch[] = {'W', 'T', 'L'};double a[3];vector<P>v;for(int i = 0; i < 3; i++) {double mx = 0;int ind;for(int j = 0; j < 3; j++) {cin >> a[j];if(a[j] > mx) {mx = a[j];ind = j;}}v.push_back(P(mx, ch[ind]));}double ans = 1;for(auto tmp : v) {printf("%c ", tmp.second);ans *= tmp.first;}ans = (ans * 0.65 - 1) * 2;printf("%.2f", ans);
}

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PAT 甲级 1011 World Cup Betting

PAT 甲级 1011 World Cup Betting

Input Specification:

Output Specification:

Sample Input:

Sample Output:

题意描述：

解题思路：

难度评测：Easy

AC代码实现：

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