共回答了18个问题采纳率：94.4%

syms a b d

a=solve('1.4/sqrt(1.5^2-1.4^2)=cos(b)*d*cos(a)/(2*1.5+d*sin(a))','a')

结果：

a =

atan((-3.+10000000000000000000000000000000.*cos(b)*(30000000000000000000000000000000.*cos(b)+(.10000000000000000000000000000000e63*cos(b)^2*d^2-.60827586206896551724137931034485e64+.67586206896551724137931034482761e63*d^2)^(1/2))/(.10000000000000000000000000000000e63*cos(b)^2+.67586206896551724137931034482761e63))/d,25997347344787260840520671338471.*(30000000000000000000000000000000.*cos(b)+(.10000000000000000000000000000000e63*cos(b)^2*d^2-.60827586206896551724137931034485e64+.67586206896551724137931034482761e63*d^2)^(1/2))/(.10000000000000000000000000000000e63*cos(b)^2+.67586206896551724137931034482761e63)/d)

atan((-3.+10000000000000000000000000000000.*cos(b)*(30000000000000000000000000000000.*cos(b)-1.*(.10000000000000000000000000000000e63*cos(b)^2*d^2-.60827586206896551724137931034485e64+.67586206896551724137931034482761e63*d^2)^(1/2))/(.10000000000000000000000000000000e63*cos(b)^2+.67586206896551724137931034482761e63))/d,25997347344787260840520671338471.*(30000000000000000000000000000000.*cos(b)-1.*(.10000000000000000000000000000000e63*cos(b)^2*d^2-.60827586206896551724137931034485e64+.67586206896551724137931034482761e63*d^2)^(1/2))/(.10000000000000000000000000000000e63*cos(b)^2+.67586206896551724137931034482761e63)/d)

>>

syms a b d

b=solve('1.4/sqrt(1.5^2-1.4^2)=cos(b)*d*cos(a)/(2*1.5+d*sin(a))','b')

结果：

b =

acos(2.5997347344787260840520671338471*(3.+d*sin(a))/d/cos(a))

d=solve('1.4/sqrt(1.5^2-1.4^2)=cos(b)*d*cos(a)/(2*1.5+d*sin(a))','d')

结果：

d =

77992042034361782521562014015413./(-25997347344787260840520671338471.*sin(a)+10000000000000000000000000000000.*cos(b)*cos(a))

>>

说明：a=α,b=β,d=d

1年前

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