521. Longest Uncommon Subsequence I

Question

Solution

题目大意：给两个字符串，找出非共同子串的最大长度

思路：字符串相等就返回-1，不等就返回长度大的那个长度

Java实现：

public int findLUSlength(String a, String b) {int aLength = a.length();int bLength = b.length();if (aLength != bLength) return Math.max(aLength, bLength);if (a.equals(b)) return -1;return aLength;
}

public int findLUSlength(String a, String b) {if (a.equals(b)) return -1;return Math.max(a.length(), b.length());
}

转载于:https://www.cnblogs.com/okokabcd/p/9634036.html

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521. Longest Uncommon Subsequence I - LeetCode

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