修改文件内容

vi命令在linux下再熟悉不过了，搭配unzip和zip还可以修改压缩包里的文件。

ps: 如果本机还没有安装zip,unzip，先执行安装命令

sudo apt-get install unzip

sudo apt-get install zip

假设现在有如下结构的目录:

HelloWorld/

└── src

└── main

├── META-INF

│   └── MANIFEST.MF

├── java

│   └── com

│   └── thxopen

│   └── demo

│   └── Main.java

└── resources

└── demo.txt

Main.java 文件内容如下：

package com.thxopen.demo;

import java.io.BufferedInputStream;

import java.io.IOException;

import java.io.InputStream;

/**

* @author Keith Shan

* @date 2019年5月7日

* @site http://www.thxopen.com

*/

public class Main {

public static void main(String[] args) {

System.out.println("Hello World!");

InputStream uri = Main.class.getClassLoader().getResourceAsStream("demo.txt");

BufferedInputStream bf = null;

try {

bf = new BufferedInputStream(uri);

byte[] b = new byte[bf.available()];

bf.read(b);

System.out.println(new String(b));

} catch (IOException e) {

e.printStackTrace();

} finally {

if (bf != null) {

try {

bf.close();

} catch (IOException e) {

e.printStackTrace();

}

}

}

}

}

代码很简单，输出一个Hello World! 然后读取resources/demo.txt文件内容并输出。

我们把项目构建成jar上传到服务器，并在服务器上执行。下面是执行输出的结果

thxopen@PC201503302026:~/work$java -jar HelloWorld.jar

Hello World!

I am Keith Shan.

现在需要修改demo.txt的内容，改变输出，不需要重新打包上传，使用vi命令即可

thxopen@PC201503302026:~/work$vi HelloWorld.jar

" zip.vim version v28

" Browsing zipfile /home/thxopen/work/HelloWorld.jar

" Select a file with cursor and press ENTER

META-INF/MANIFEST.MF

com/

com/thxopen/

com/thxopen/demo/

com/thxopen/demo/Main.class

demo.txt

META-INF/

META-INF/HelloWorld.kotlin_module

然后会列出jar里面的内容，把光标移动到需要编辑的文件，回车即可编辑。

ps: 如果文件比较多，可以使用/filename 来查找定位

进入文件编辑状态后，操作就和vi命令一样，这里我新增I am the new String. 内容，:wq!保存退出vi，然后:exit退出jar编辑状态。

重新执行

thxopen@PC201503302026:~/work$java -jar HelloWorld.jar

Hello World!

I am Keith Shan.

I am the new String.

从输出可以看到demo.txt内容被成功修改

替换文件

修改文件内容对于.class文件来说似乎就不行了，那只能直接替换文件，如果替换文件呢？

我修改Main.java文件，修改后内容如下：

package com.thxopen.demo;

/**

* @author Keith Shan

* @date 2019年5月7日

* @site http://www.thxopen.com

*/

public class Main {

public static void main(String[] args) {

System.out.println("Class file modified");

}

}

我把编译好的class文件放到 /com/thxopen/demo目录下，如下所示

thxopen@PC201503302026:~/work$tree

.

├── HelloWorld.jar

└── com

└── thxopen

└── demo

└── Main.class (重新编译好的文件)

3 directories, 2 files

执行如下命令把文件替换到jar中

thxopen@PC201503302026:~/work$jar -uvf HelloWorld.jar com/thxopen/demo/Main.class

adding: com/thxopen/demo/Main.class(in = 557) (out= 351)(deflated 36%)

重新执行，class文件已经被替换

thxopen@PC201503302026:~/work$java -jar HelloWorld.jar

Class file modified

附：jar命令的基本用法

thxopen@PC201503302026:~/work$jar

Usage: jar {ctxui}[vfmn0PMe] [jar-file] [manifest-file] [entry-point] [-C dir] files ...

Options:

-c create new archive

-t list table of contents forarchive

-x extract named (or all) files from archive

-u update existing archive 更新存在的压缩包

-v generate verbose output on standard output 生成日志到标准输出

-f specify archive file name 指定压缩包名称

-m include manifest information from specified manifest file

-n perform Pack200 normalization after creating a new archive

-e specify application entry point forstand-alone application

bundled into an executable jar file

-0 store only; use no ZIP compression

-P preserve leading '/' (absolute path) and ".." (parent directory) components from file names

-M donot create a manifest file forthe entries

-i generate index information forthe specified jar files

-C change to the specified directory and include the following file

If any file is a directory thenit is processed recursively.

The manifest file name, the archive file name and the entry point name are

specified inthe same order as the 'm', 'f' and 'e' flags.

Example 1: to archive two class files into an archive called classes.jar:

jar cvf classes.jar Foo.class Bar.class

Example 2: use an existing manifest file 'mymanifest' and archive all the

files inthe foo/ directory into 'classes.jar':

jar cvfm classes.jar mymanifest -C foo/ .