java解决 No enclosing instance of type XXX is accessible的问题

有些时候我们要把Activity的一些实现类移到java类里来实现，比如把写以下两个类:

在LifeCircle这个类中:

public class LifeCircle {public class Mybroadcast extends BroadcastReceiver {@Overridepublic void onReceive(Context context, Intent intent) {}}
}

如果在Activity这样去new:

public class Settings extends Activity {@Overrideprotected void onCreate(Bundle savedInstanceState) {super.onCreate(savedInstanceState);setContentView(R.layout.test_layout);LifeCircle lifeCircle = new LifeCircle(this);Mybroadcast cast = new Mybroadcast();}}

编译器会报一个错误:

 - No enclosing instance of type LifeCircle is accessible. Must qualify the allocation with an enclosing instance of type LifeCircle (e.g. x.new A() where x is an instance of LifeCircle).

一种解决方法是把Mybroadcast定义为static class

令一种这样来弄:

package com.example.shoplistdownload;import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.content.IntentFilter;public class LifeCircle {Context mContext;private static LifeCircle sInstance;private Mybroadcast mBroadcast;private Settings mInstance;LifeCircle(Context context) {mContext = context;mInstance = (Settings)context;}public static LifeCircle getIntance(Context context) {if (sInstance == null) {sInstance = new LifeCircle(context);}return sInstance;}public class Mybroadcast extends BroadcastReceiver {@Overridepublic void onReceive(Context context, Intent intent) {}}public void registerBroadcaster() {mBroadcast = new Mybroadcast();IntentFilter filter = new IntentFilter();filter.addAction("com.example.action");mInstance.registerReceiver(mBroadcast, filter);}
}

public class Settings extends Activity {@Overrideprotected void onCreate(Bundle savedInstanceState) {super.onCreate(savedInstanceState);setContentView(R.layout.test_layout);LifeCircle lifeCircle = new LifeCircle(this);lifeCircle.registerBroadcaster();}}

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