我是Java的新手,我自己也在学习.我尝试重载方法时遇到了麻烦.这是代码

public static void main(String[] args) {

calculateScore();

calculateScore(500);

calculateScore("Duy", 600);

calcFeetAndInchesToCentimetres(100, 3.5);

calcFeetAndInchesToCentimetres(100*12 + 3.5);

}

public static double calcFeetAndInchesToCentimetres(double feet, double inches) {

if (feet >= 0 && inches >= 0 && inches <= 12) {

double footToInches = feet * 12;

double centimetres = (inches + footToInches) * 2.54;

System.out.println("The value in centimetres is " + centimetres + " cm.");

return centimetres;

} else {

return -1;

}

}

public static double calcFeetAndInchesToCentimetres(double inches) {

if (inches >= 0){

double inchesToFeet = inches / 12;

double inchesRemain = inches - (inchesToFeet * 12);

calcFeetAndInchesToCentimetres(inchesToFeet, inchesRemain);

return 0;

} else {

return -1;

}

我的问题是当我从第二种方法中获取返回0时,调试器会说“缺少return语句”.然后我尝试将返回calcFeetAndInchesToCentimetres(inches);,它可以工作,但程序运行了大约数千次.

然后我把返回0,一切都OK.但我不明白为什么我不能把返回calcFeetAndInchesToCentimetres(英寸);当上面的方法(带有2个参数)得到它时,为什么我需要一个return语句.如果我想在执行第二种方法时转换厘米的值(仅使用“inches”参数),我该怎么做？

我在块代码中意识到的另一件事

double inchesToFeet = inches / 12;

double inchesRemain = inches - (inchesToFeet * 12);

calcFeetAndInchesToCentimetres(inchesToFeet, inchesRemain);

inchesRemain将为0？但该方法效果很好.当我改变inchesToFeet =英寸％12时,它只是没有显示任何内容.为什么？

解决方法:

它应该只是：

public static double calcFeetAndInchesToCentimetres(double inches) {

if (inches >= 0){

double inchesToFeet = inches / 12;

double inchesRemain = inches - (inchesToFeet * 12);

return calcFeetAndInchesToCentimetres(inchesToFeet, inchesRemain);

} else {

return -1;

}

}

你说你已经尝试过返回calcFeetAndInchesToCentimetres(英寸);但这只是递归地调用你的方法而且它会永远递归,因为没有停止条件.

标签：java,return,overloading,methods

来源： https://codeday.me/bug/20190724/1524847.html