java 日期做差 ： 场景 判断过期

public static String dateDiff(String startTime, String endTime,

String format) {

// 按照传入的格式生成一个simpledateformate对象

SimpleDateFormat sd = new SimpleDateFormat(format);

long nd = 1000 * 24 * 60 * 60;// 一天的毫秒数

long nh = 1000 * 60 * 60;// 一小时的毫秒数

long nm = 1000 * 60;// 一分钟的毫秒数

long ns = 1000;// 一秒钟的毫秒数

long diff;

long day = 0;

long hour = 0;

long min = 0;

long sec = 0;

// 获得两个时间的毫秒时间差异

try {

diff = sd.parse(endTime).getTime() - sd.parse(startTime).getTime();

day = diff / nd;// 计算差多少天

hour = diff % nd / nh + day * 24;// 计算差多少小时

min = diff % nd % nh / nm + day * 24 * 60;// 计算差多少分钟

sec = diff % nd % nh % nm / ns;// 计算差多少秒

} catch (ParseException e) {

e.printStackTrace();

}

return day + "天" + (hour - day * 24) + "小时"

+ (min - day * 24 * 60) + "分钟";

}

分转换为小时天

static String timeStamp(int minute){

String StatusMinute = "";

int day= minute/60/24;

int hour = minute/60%24;

int min= minute % 60;

if (day > 0)

{

StatusMinute= day + "天";

}

if (hour>0)

{

StatusMinute += hour + "小时";

}

if (min>0)

{

StatusMinute += min + "分钟";

}

System.out.println(StatusMinute);

return StatusMinute;

}

拆分数据：

private List> sqlitSql(List str1,String originSql) {

int step = 1000;

int num = str1.size() / step;

if (num > 0) {

num++;

}

List> parkLotList = new ArrayList>();

int n = 0;

for(int i=1; i<=num;i++){

StringBuilder str2 = new StringBuilder() ;

for (int j=n;j

if(j==str1.size()){

break;

}

System.out.println("j+"+j);

str2.append("'");

str2.append(str1.get(j));

str2.append("'");

if(j!=i*step-1&&j!=str1.size()-1){

str2.append(",");

}

}

String parkLotSql = originSql+str2 +") ";

int nu = parkLotSql.length();

List> parkLotList1 = cgyJdbcTemplate.queryForList(parkLotSql);

parkLotList.addAll(parkLotList1);

n=i*step;

}

return parkLotList;

}

生成6位不重复的随机字符：

public String getlinkNo() {

String linkNo = "";

// 用字符数组的方式随机

String model = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";

char[] m = model.toCharArray();

for (int j = 0; j < 6; j++) {

char c = m[(int) (Math.random() * 36)];

// 保证六位随机数之间没有重复的

if (linkNo.contains(String.valueOf(c))) {

j--;

continue;

}

linkNo = linkNo + c;

}

return linkNo;

}