LeetCode 646. Maximum Length of Pair Chain

题目：
You are given n pairs of numbers. In every pair, the first number is always smaller than the second number.

Now, we define a pair (c, d) can follow another pair (a, b) if and only if b < c. Chain of pairs can be formed in this fashion.

Given a set of pairs, find the length longest chain which can be formed. You needn’t use up all the given pairs. You can select pairs in any order.

Example 1:

Input: [[1,2], [2,3], [3,4]]
Output: 2
Explanation: The longest chain is [1,2] -> [3,4]

思路：我是先按vector的第一个数进行排序然后遍历对比，没用到dp，具体思路见注释~

代码：

class Solution {
public:int findLongestChain(vector<vector<int>>& pairs) {if (pairs.size() == 0){//如果pairs为空，直接返回0return 0;}int count = 1;sort(pairs.begin(), pairs.end());//选按第一个数进行排序vector<vector<int> >::iterator iter = pairs.begin();vector<vector<int> >::iterator iter1 = ++pairs.begin();for (; iter1 != pairs.end();){if ((*iter1)[0] > (*iter)[1]){//如果后一对的第一个数比前一对的第二个数大iter = iter1;//更新iter和iter1++iter1;++count;//计数}else if ((*iter1)[1] <= (*iter)[1]){//如果后一对的第二个数比前一对的第二个数要小iter = iter1;//只更新iter,iter1++iter1;}else{//否则，这个iter1对应的对不满足，直接只更新iter1++iter1;}}return count;}
};

输出结果： 59ms

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