Is Derek lying?

Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 0 Accepted Submission(s): 0

题目链接：点击打开链接

Problem Description

Derek and Alfia are good friends.Derek is Chinese,and Alfia is Austrian.This summer holiday,they both participate in the summer camp of Borussia Dortmund.During the summer camp,there will be fan tests at intervals.The test consists of N choice questions and each question is followed by three choices marked “A” “B” and “C”.Each question has only one correct answer and each question is worth 1 point.It means that if your answer for this question is right,you can get 1point.The total score of a person is the sum of marks for all questions.When the test is over,the computer will tell Derek the total score of him and Alfia.Then Alfiawill ask Derek the total score of her and he will tell her: “My total score is X,your total score is Y.”But Derek is naughty,sometimes he may lie to her. Here give you the answer that Derek and Alfia made,you should judge whether Derek is lying.If there exists a set of standard answer satisfy the total score that Derek said,you can consider he is not lying,otherwise he is lying.

Input

The first line consists of an integer T,represents the number of test cases.

For each test case,there will be three lines.

The first line consists of three integers N,X,Y,the meaning is mentioned above.

The second line consists of N characters,each character is “A” “B” or “C”,which represents the answer of Derek for each question.

The third line consists of N characters,the same form as the second line,which represents the answer of Alfia for each question.

Data Range:1≤N≤80000,0≤X,Y≤N,∑Ti=1N≤300000

Output

For each test case,the output will be only a line.

Please print “Lying” if you can make sure that Derek is lying,otherwise please print “Not lying”.

Sample Input
2
3 1 3
AAA
ABC
5 5 0
ABCBC
ACBCB

Sample Output
Not lying
Lying

题意：D和A是好朋友，同时参加考试比赛，比赛完后，系统会告诉D他们俩的总得分情况，D比较顽皮，他有时不会向A汇报正确的得分情况，做对一题得一分，告诉你有多少道题，以及D告诉A他和A的总分，然后分别给出D和A的答案，问你D是否对A撒谎了。

分析：假设一个人的答案全部正确为n，c是他们一样答案的个数，那么他们的的总得分一定不大于n+c，他们得分差一定不大于n-c。

#include<cstdio>
#include<cstring>
#include<cmath>
using namespace std;
char s1[300010],s2[300010];
int main()
{int t;scanf("%d",&t);while(t--){int a,b,n;scanf("%d %d %d",&n,&a,&b);scanf("%s",s1);scanf("%s",s2);int c=0;for(int i=0;i<n;i++){if(s1[i]==s2[i]) c++;//c是记录他们答案相同的个数}if(a+b<=n+c&&abs(a-b)<=n-c){printf("Not lying\n");}else{printf("Lying\n");}}return 0;
}

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