aspose合并单元格

工作中遇到处理word模板用到了aspose插件，其中遇到了合并单元格，其中分为上下单元格合并，以及左右单元格合并

1.一行中相邻单元格合并

 //合并所有左右相邻单元格一致的行public static void hbCells( HashMap<String,Object> m1,String filepath ) throws Exception{Map rs=getcf(m1);Iterator iterator = rs.keySet().iterator(); Map rr = new HashMap();//获取重复数据的合并行的坐标while (iterator.hasNext()){ Object value = iterator.next(); List<String> result = (List) rs.get(value); //System.out.println(result);List list = new ArrayList();List<Integer> rowlist = new ArrayList<Integer>();List<Integer> celllist = new ArrayList<Integer>();for( String js:result){String jj= getTextCellRow(filepath,js); int row=Integer.parseInt(jj.split(",")[0]);int cell=Integer.parseInt(jj.split(",")[1]);rowlist.add(row);celllist.add(cell);}list=getCellQJ(rowlist,celllist);if(list.size()>0){rr.put(value, list);}}//2处理合并Iterator ite = rr.keySet().iterator(); while (ite.hasNext()){ Object value = ite.next(); List<String> result = (List) rr.get(value); hbCell(filepath,result,filepath);}}public static List<String> getCellQJ(List<Integer> rowList,List<Integer> cellList) throws Exception{List<String> list = new ArrayList<String>();int maxrow= Collections.max(rowList);int maxcell= Collections.max(cellList);int minrow= Collections.min(rowList);int mincell= Collections.min(cellList);if(maxrow==minrow){int size=rowList.size();int fw=maxcell-mincell+1;//连续的单元格if(size==fw){list.add(mincell+","+minrow);list.add(maxcell+","+minrow);}}return list;}//合并左右单元public static void hbCell( String filepath, List<String> result,String savefile) throws Exception{int row=Integer.parseInt(result.get(0).split(",")[1]);int mincell=Integer.parseInt(result.get(0).split(",")[0]);int maxCell=Integer.parseInt(result.get(1).split(",")[0]);Document doc = new Document(filepath);Table table = (Table) doc.getChild(NodeType.TABLE, 0, true); //第1个表格// We want to merge the range of cells found in between these two cells.Cell cellStartRange = table.getRows().get(row).getCells().get(mincell); //第2行第1列Cell cellEndRange = table.getRows().get(row).getCells().get(maxCell); //第3行第1列// Merge all the cells between the two specified cells into one.mergeCellshx(cellStartRange, cellEndRange);doc.save(savefile);}//合并一行的相邻单元格public static void mergeCellshx(Cell startCell, Cell endCell) {Table parentTable = startCell.getParentRow().getParentTable();double Cellwidth=0;;//Table parentTable2 = endCell.getParentRow().getParentTable();// Find the row and cell indices for the start and end cell.Point startCellPos = new Point(startCell.getParentRow().indexOf(startCell), parentTable.indexOf(startCell.getParentRow()));Point endCellPos = new Point(endCell.getParentRow().indexOf(endCell), parentTable.indexOf(endCell.getParentRow()));// Create the range of cells to be merged based off these indices. Inverse each index if the end cell if before the start cell.Rectangle mergeRange = new Rectangle(Math.min(endCellPos.x, startCellPos.x),Math.min(endCellPos.y, endCellPos.y),Math.abs(endCellPos.x-startCellPos.x)+1 ,1);//1,2,0,18 h,w,x,yfor (Row row : parentTable.getRows()) {for (Cell cell : row.getCells()) {Point currentPos = new Point(row.indexOf(cell), parentTable.indexOf(row));// Check if the current cell is inside our merge range then merge it.0,18  1,18if (mergeRange.contains(currentPos)) { Cellwidth+= cell.getCellFormat().getWidth();if (currentPos.y == mergeRange.y)cell.getCellFormat().setVerticalMerge(CellMerge.FIRST);elsecell.getCellFormat().setVerticalMerge(CellMerge.NONE);if (currentPos.x==mergeRange.x)cell.getCellFormat().setHorizontalMerge(CellMerge.FIRST);elsecell.getCellFormat().setHorizontalMerge(CellMerge.PREVIOUS);}}}startCell.getCellFormat().setWidth(Cellwidth);}

2.处理合并上下单元格

//合并所有上下单元格一致的行public static void hbRows( HashMap<String,Object> m1,String filepath ) throws Exception{Map rs=getcf(m1);Iterator iterator = rs.keySet().iterator(); Map rr = new HashMap();Map cr = new HashMap();//获取重复数据的合并行的坐标while (iterator.hasNext()){ Object value = iterator.next(); List<String> result = (List) rs.get(value); //System.out.println(result);List listr = new ArrayList();List listc = new ArrayList();List<Integer> rowlist = new ArrayList<Integer>();List<Integer> celllist = new ArrayList<Integer>();for( String js:result){String jj= getTextCellRow(filepath,js); if(StringUtils.isNotEmpty(jj)){int row=Integer.parseInt(jj.split(",")[0]);int cell=Integer.parseInt(jj.split(",")[1]);rowlist.add(row);celllist.add(cell);}}if(rowlist.size()>0){listr=getRowQJ(rowlist,celllist);if(listr.size()>0){rr.put(value, listr);}listc=getCellQJ(rowlist,celllist);if(listc.size()>0){cr.put(value, listc);}}}//2处理合并//1.合并上下相同的单元格Iterator ite = rr.keySet().iterator(); while (ite.hasNext()){ Object value = ite.next(); List<String> result = (List) rr.get(value); hbRow(filepath,result,filepath);}//2.合并左右相同的单元格Iterator itc = cr.keySet().iterator(); while (itc.hasNext()){ Object value = itc.next(); List<String> result = (List) cr.get(value); hbCell(filepath,result,filepath);}}//合并上下单元public static void hbRow( String filepath, List<String> result,String savefile) throws Exception{int minrow=Integer.parseInt(result.get(0).split(",")[0]);int cell=Integer.parseInt(result.get(0).split(",")[1]);int maxrow=Integer.parseInt(result.get(1).split(",")[0]);Document doc = new Document(filepath);Table table = (Table) doc.getChild(NodeType.TABLE, 0, true); //第1个表格// We want to merge the range of cells found in between these two cells.Cell cellStartRange = table.getRows().get(minrow).getCells().get(cell); //第2行第1列Cell cellEndRange = table.getRows().get(maxrow).getCells().get(cell); //第3行第1列// Merge all the cells between the two specified cells into one.mergeCells(cellStartRange, cellEndRange);doc.save(savefile);}//获取区间row大小必须列一致public static List<String> getRowQJ(List<Integer> rowList,List<Integer> cellList) throws Exception{List<String> list = new ArrayList<String>();int maxrow= Collections.max(rowList);int maxcell= Collections.max(cellList);int minrow= Collections.min(rowList);int mincell= Collections.min(cellList);if(maxcell==mincell){int size=rowList.size();int fw=maxrow-minrow+1;//连续的单元格if(size==fw){//只有第一列if(mincell==0){list.add(minrow+","+mincell);list.add(maxrow+","+mincell);}}}return list;}//获取相同value的keypublic static Map getcf(Map<String, Object> map){Map rs = new HashMap();Map values = new HashMap();List list = new ArrayList(); Iterator iterator = map.keySet().iterator(); while (iterator.hasNext()) { Object key = iterator.next(); Object value = map.get(key); if (map.containsValue(value)) { if (values.containsKey(value)) { list = (List) values.get(value); } else { list = new ArrayList(); } list.add(key); values.put(value, list); } } iterator = values.keySet().iterator(); while (iterator.hasNext()) { Object value = iterator.next(); List result = (List) values.get(value); if (result.size() > 1) { rs.put(value, result);// System.out.println("value :" + value + "  -> keys:" + result.toString()); } } return rs; }//获取内容的行列public static String getTextCellRow(String FilePath,String data) throws Exception{Document doc;String tt="";String s = "<License><Data><Products><Product>Aspose.Total for Java</Product><Product>Aspose.Words for Java</Product></Products><EditionType>Enterprise</EditionType><SubscriptionExpiry>20991231</SubscriptionExpiry><LicenseExpiry>20991231</LicenseExpiry><SerialNumber>8bfe198c-7f0c-4ef8-8ff0-acc3237bf0d7</SerialNumber></Data><Signature>sNLLKGMUdF0r8O1kKilWAGdgfs2BvJb/2Xp8p5iuDVfZXmhppo+d0Ran1P9TKdjV4ABwAgKXxJ3jcQTqE/2IRfqwnPf8itN8aFZlV3TJPYeD3yWE7IT55Gz6EijUpC7aKeoohTb4w2fpox58wWoF3SNp6sK6jDfiAUGEHYJ9pjU=</Signature></License>";ByteArrayInputStream is = new ByteArrayInputStream(s.getBytes());License license = new License();license.setLicense(is);doc = new Document(FilePath);//替换表格//获取第一个表格Table table = (Table)doc.getChild(NodeType.TABLE, 0, true);if(table!=null){DocumentBuilder builder = new DocumentBuilder(doc);RowCollection rows = table.getRows();
//          System.out.println("rows==="+rows.getCount());for (int i = 0; i < rows.getCount(); i++) {Row row = rows.get(i);for(int j=0; j<row.getCells().getCount(); j++){Cell cell=row.getCells().get(j);if(null != cell ){String text = cell.getText().trim();if(null != text && !"".equals(text)){if(text.equals(data)){tt=i+","+j;}}                  }}}}return tt;}/**合并列* Merges the range of cells found between the two specified cells both* horizontally and vertically. Can span over multiple rows.* @param startCell* @param endCell*/public static void mergeCells(Cell startCell, Cell endCell) {Table parentTable = startCell.getParentRow().getParentTable();// Find the row and cell indices for the start and end cell.Point startCellPos = new Point(startCell.getParentRow().indexOf(startCell), parentTable.indexOf(startCell.getParentRow()));Point endCellPos = new Point(endCell.getParentRow().indexOf(endCell), parentTable.indexOf(endCell.getParentRow()));// Create the range of cells to be merged based off these indices. Inverse each index if the end cell if before the start cell.Rectangle mergeRange = new Rectangle(Math.min(startCellPos.x, endCellPos.x), Math.min(startCellPos.y, endCellPos.y), Math.abs(endCellPos.x-startCellPos.x) + 1,Math.abs(endCellPos.y-startCellPos.y) + 1);for (Row row : parentTable.getRows()) {for (Cell cell : row.getCells()) {Point currentPos = new Point(row.indexOf(cell), parentTable.indexOf(row));// Check if the current cell is inside our merge range then merge it.if (mergeRange.contains(currentPos)) {if (currentPos.x==mergeRange.x)cell.getCellFormat().setHorizontalMerge(CellMerge.FIRST);elsecell.getCellFormat().setHorizontalMerge(CellMerge.PREVIOUS);if (currentPos.y == mergeRange.y)cell.getCellFormat().setVerticalMerge(CellMerge.FIRST);elsecell.getCellFormat().setVerticalMerge(CellMerge.PREVIOUS);}}}}

3测试方法

合并map中value值相同的相邻单元格

String filepath="E://AAA//1.doc";

HashMap<String,Object> m1 = new HashMap<String,Object>();
           m1.put("1","黄");
           m1.put("11","黄");
           m1.put("3","涛");
           m1.put("4","涛");
           hbCells(m1,filepath);
           hbRows(m1,filepath);

4.文件的表格样式

5.合并之后

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