SCU - 4486 Easy Problem VI

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求和，前n项和，然后减去二倍n范围内2的次方倍的和。

#include<bits/stdc++.h>
#define MOD 100000007
#define ll long long
const int maxn=2e2+20;
using namespace std;
int dp[maxn];
struct node{int x,y;
}a[maxn];
int cmp(node a,node b){if(a.y==b.y) return a.x<b.x;return a.y>b.y;
}
int main(){ll n,sum,mul,t=1;int i,T;scanf("%d",&T);while(T--){sum=0,t=1;scanf("%lld",&n);sum=n*(n+1)/2;mul=1;for(i=1;i<=64;++i){mul*=2;if(mul>n) break;t+=mul;}//printf("%lld\n",t);printf("%lld\n",sum-2*t);}return 0;
}

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