在第一篇文章中使用的json方法。能够依照须要仅仅处理须要的属性，但却要求属性不能是复杂的类型，比如泛型，数组。其它用户自己定义的类等，限制太多，于是自己看看能不能改进，想不到Newtonsoft.Json提供有相关的接口，仅仅须要实现就能够了。

仅仅须要继承DefaultContractResolver，并改写一个方法就能够了。

核心代码：

 /// <summary>/// 对象转为json，全部属性都输出/// </summary>/// <typeparam name="ObjType"></typeparam>/// <param name="obj"></param>/// <returns></returns>public static string ObjToJsonString<ObjType>(ObjType obj) where ObjType : class{string s = JsonConvert.SerializeObject(obj);return s;}/// <summary>/// 对象转为json，仅仅输出部分属性/// </summary>/// <typeparam name="T">对象类型</typeparam>/// <param name="t">对象类型值</param>/// <param name="propertyInfos">须要json处理的属性名称。以逗号分隔</param>/// <returns></returns>public static string ObjToJsonString<T>(T t, string propertyInfos) where T : class{string[] cols = propertyInfos.Split(new char[] { ',' }, StringSplitOptions.RemoveEmptyEntries);List<string> _propertyNames = new List<string>();foreach (string col in cols){  string   colTemp = col.ToLower().Trim();if (!_propertyNames.Contains(colTemp)){_propertyNames.Add(colTemp);}}string s = JsonConvert.SerializeObject(t, Formatting.Indented, new JsonSerializerSettings { ContractResolver = new DynamicContractResolver(_propertyNames) });return s;}/// <summary>/// json转为对象/// </summary>/// <typeparam name="ObjType"></typeparam>/// <param name="JsonString"></param>/// <returns></returns>public static ObjType JsonStringToObj<ObjType>(string JsonString) where ObjType : class{          ObjType s = JsonConvert.DeserializeObject<ObjType>(JsonString);return s;}class DynamicContractResolver : DefaultContractResolver{private readonly List<string> _propertyNames;public DynamicContractResolver(List<string> propertyNames){_propertyNames = propertyNames;}/// <summary>/// 假设属性是对象。须要把这个对象的属性也传给propertyNames，/// 否则处理这个对象属性时，就不包括相应的属性值/// </summary>/// <param name="type"></param>/// <param name="memberSerialization"></param>/// <returns></returns>protected override IList<JsonProperty> CreateProperties(Type type, MemberSerialization memberSerialization){IList<JsonProperty> properties = base.CreateProperties(type, memberSerialization);IList<JsonProperty> propertiesReturn = new List<JsonProperty>();//须要json处理的属性foreach (JsonProperty item in properties){ string PropertyNameTemp = item.PropertyName.ToLower().Trim();if (_propertyNames.Contains(PropertyNameTemp)){propertiesReturn.Add(item);                   }}return propertiesReturn;}}