LeetCode之Single Number

1、题目

Given an array of integers, every element appears twice except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

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2、代码实现

代码实现1

public static int singleNumber1(int nums[]) {if (nums == null) return 0;int length = nums.length;int count = 0;for (int i = 0; i < length ; i++) {for (int j = 0; j < length; j++) {if (i != j) {if (nums[i] == nums[j]) continue;else {count++;  }}}if (count == length - 1)return nums[i];count = 0;}      return 0;

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LeetCode之Single Number

1、题目

2、代码实现

代码实现1

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